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vitfil [10]
3 years ago
6

An electron moves through a region of crossed electric and magnetic fields. The electric field E = 3059 V/m and is directed stra

ight down. The magnetic field B = 1.14 T and is directed to the left. For what velocity v of the electron into the paper will the electric force exactly cancel the magnetic force?
Physics
1 answer:
dangina [55]3 years ago
7 0

Answer:

v = 2683.33 m/s

Explanation:

The magnetic force and the electric force on the electron must be the same, in order for them to cancel each other:

Electric\ Force = Magnetic\ Force\\Eq = qvBSin\theta \\\\v = \frac{E}{BSin\theta}

where,

v = velcoity of electron = ?

E = Electric Field = 3059 V/m

B = Magnetic Field = 1.14 T

θ = Angle between velocity and magnetic field = 90°

Therefore,

v = \frac{3059\ V/m}{(1.14\ T)Sin90^o}

<u>v = 2683.33 m/s</u>

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Solving a series circuit, did I do this correctly? ​
nirvana33 [79]
  • The total resistance in the circuit is 16 Ohms.
  • The total current in the circuit is 0.5 Ampere.
  • The current at R_1 is 0.5 Ampere.
  • The current at R_3 is 0.5 Ampere.
  • The voltage drop atR_1 is 4 volts.
  • The voltage drop at R_2 is 2.5  volts.
  • The voltage drop at R_3 is 1.5 volts.
  • The total power consumed by the circuit is 4watts
  • The power consumed at R_1 is 2 watts
  • The power consumed at R_2 is 1.25 watts

Given:

The voltage across the circuit = V = 8 V

The resistors connected are in series:

R_1=8 \Omega, R_2=5\Omega ,R_3=3 \Omega

To find:

The values of from 1 to 10.

Solution

The voltage across the circuit = V = 8 V

  • The total resistance in the circuit  = R_{eq}

R_{eq}=R_1+R_2+R_3\\=8 \Omega +5 \Omega + 3\Omega =16\omega

  • The total current in the circuit = I

V=IR_{eq}\\I=\frac{V}{R_{eq}}=\frac{8 V}{16 \Omega}=0.5 A (Ohm's law)

  • For series combinations, the current in each resistor remains the same.

So, the current in R_1, R_2 \&R_3:

I_1= I_2= I_3=I=0.5 A\\

  • The voltage drop across at R_1 = V_1

The current across  R_1 = I = 0.5 A

V_1=I\times R_1\\\\=0.5A\times 8\Omega = 4 V

  • The voltage drop across at R_2 =V_2

The current across  R_2 = I = 0.5 A

V_2=I\times R_2\\\\=0.5A\times 5\Omega = 2.5 V

  • The voltage drop across at R_3 = V_3

The current across  R_3 = I = 0.5 A

V_3=I\times R_3\\\\=0.5A\times 3\Omega = 1.5 V

  • The total power consumed by circuit:

P= V\times I \\\\= 0.5 A\times 8 V = 4 watt

  • Power consumed at R_1:

P_1=V_1\times I\\\\= 4V\times 0.5A = 2 watt

  • Power consumed at R_2:

P_2=V_2\times I\\\\= 2.5 V\times 0.5A = 1.25 watt

  • Power consumed at R_3:

P_3=V_3\times I= \\\\1.5 V\times 0.5A = 0.75 watt

Learn more about, current, voltage, resistance, and power of the circuit here:

brainly.com/question/11683246?referrer=searchResults

brainly.com/question/1430450?referrer=searchResults

5 0
2 years ago
1. Monique is nine weeks into her pregnancy, and she had an appointment with her doc tor today. She is very happy and excited be
djyliett [7]

Since Monique is able to hear the heartbeats of her baby, it's the Fetus stage of pregnancy when the body starts developing inside the womb.

<u>Explanation:</u>

The Fetus Stage of Pregnancy:

Once the 4th-7th weeks of pregnancy passed, the embryo start developing inside the womb of the mother and the respective symptoms reflects. This is the Fetus stage of pregnancy which occur in approximately around the 10th week of pregnancy.

In the fetus stage, the human body begins to develop inside the womb. In this phase, most of the organs are developed and the limbs starts to form firmly. The Fetus stage comes after the Embryo stage but usually, the transition varies according to the growth and circumstances of the atmosphere.

But, what is certain is that the mother can feel the impulse and heartbeats of the baby inside her womb which is an exciting and memorable feeling for her.

7 0
4 years ago
Achargingbullelephantwithamassof5240kgcomesdi- rectly toward you with a speed of 4.55 m/s. You toss a 0.150-kg rubber ball at th
Ierofanga [76]

Answer:

Given:

Mass of elephant = 5240 kg

The initial speed of the elephant = 4.55 m/s

Mass of the rubber ball, m, = 0.15 kg

Inital speed of the rubber ball, v = 7.81 m/s

On substitution  in V_{2f} = [\frac{2m_{1} }{m_{1} +m_{2} } ]V_{1f} + [\frac{m_{2}-m_{1}}{m_{1}+m_{2}  } ] v_{2f}

V_{2f} = [\frac{2*5240_{} }{5240_{} +0.15_{} } ](-4.55_{}) + [\frac{0.15_{}-5240_{}}{5240_{}+0.15_{}  } ] (7.81_{})

a) The negatıve sign shows that the ball bounces back in the direction opposite  to the incident

b)  it is clear that the velocity of the ball increases and therefore it is kinetic energy . The ball gains kinetic energy from the elephant.

8 0
3 years ago
Which of the following statements characterizing types of waves are true?
Tasya [4]

Answer:

a and b.

Explanation:

In general  types of wave

1. Transverse wave  :

    In these waves particle are vibrate perpendicular to motion of waves.

 Ex : Electromagnetic wave , Radio wave .

2. Longitudinal wave :

   In these waves particle are vibrate along the motion of waves.

 Ex : Sound wave

Mechanical wave  :

1 .These are transverse wave or Longitudinal wave or combination of them .

2.These waves required medium for propagation.

3. The particle are vibrate perpendicular to motion of waves.

So the option a and b are correct.

7 0
3 years ago
When is the zebra in motion? When is it not moving?
frosja888 [35]
Motion depends on what your reference point is. So a good reference point is  a tree or a sign, something that is not moving. So if the zebra is walking towards the tree he/she is getting closer to the tree, He/she is in motion. But if the zebra and the tree never get closer or farther apart the zebra is not in motion. HOPE THIS HELPED!! ;D
4 0
3 years ago
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