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kati45 [8]
3 years ago
15

If sin θ =8/9. Find cot θ.

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
7 0

Step-by-step explanation:

✧ \underline{ \underline{ \large{ \tt{G\: I \: V \: E\: N}}} }:

  • \large{ \tt{sin \:  \theta =  \frac{8}{9}}} Here , Perpendicular ( p ) = 8 & hypotenuse ( h ) = 9

♨ \underline{ \underline{ \large{ \tt{ T \: O \:  \: F \: I\: N\: D}}}} :

  • \large{ \tt{cot  \: \theta}}

♨ \underline{ \underline{ \large{ \tt{S \: O \: L\: U \: T\: I\: O \: N}}}} :

  • First, Find the base ( b ) using Pythagoras theorem :

☪ \boxed{ \bf{ {h}^{2} =  {p}^{2} +  {b}^{2}   }}

~Plug all the known values and then simplify!

⇾ \large{ \bf{ {9}^{2}  =  {8}^{2}  +  {b}^{2} }}

⇾ \large{ \bf{81 = 64 +  {b}^{2} }}

⇾ \large{ \bf{64 +  {b}^{2}  = 81}}

⇾ \large{ \bf{ {b}^{2}  = 81 - 64}}

⇾ \large{ \bf{ {b}^{2}  = 17}}

⇾ \large{ \bf{b =  \sqrt{17}}}

  • Now , Find the value of cot θ

We know ;

⟿ \large{ \bf{cot \theta =  \frac{b}{p}  =  \boxed{ \bf{ \frac{ \sqrt{17} }{8}}}}}

⤷ \boxed{ \boxed{ \underline{ \large{ \tt{Our \: Final \: Answer :  { \tt{ \frac{ \sqrt{17} }{8} }}}}}}}

( Correct me if I'm wrong )

Hope I helped ! ♡

Have a wonderful day / night ! ツ

☄ Let me know if you have any questions regarding my answer !

\underline{ \underline{ \mathfrak{Carry \: On \: Learning}}} !! ✎

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

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