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irina1246 [14]
3 years ago
6

A bag has 4 yellow, 6 red, 2 green, and 8 purple marbles. What is the probability of picking a purple marble, not replacing it,

and then picking another purple marble?
Mathematics
1 answer:
Dominik [7]3 years ago
8 0

Answer:

The probability of picking two consecutive purple marbles without replacement is 14.72%.

Step-by-step explanation:

Initially, there are 4+6+2+8 = 20 total marbles.

The probability of picking a purble marble is

P_{1} = \frac{number of purple marbles}{number of total marbles}

P_{1}= \frac{8}{20} = 0.4

Since there are no replacements, there are now 19 total marbles, 7 of which are purple. So, the probability of picking another purple marble is

P_{2} = \frac{7}{19} = 0.368

The probability P of picking a purble marble(P_{1}), not replacing it, and then picking another purple marble(P_{2}) is:

P = P_{1}*P_{2} = 0.4*0.368  = 0.1472 = 14.72%

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Nostrana [21]
Let the numbers be x and y

x= y-2.... (1)
and, 2y = 16 + 4x.... (2)

putting the value of x from (1) in (2),

2y = 16 + 4x
=> 2y = 16 + 4(y-2)
=> 2y = 16 + 4y - 8
=> 2y = 8 + 4y
=> 2y - 4y = 8
=> -2y = 8
=> y =-8/2
=> y= -4

and x = -4-2 = -6

hence , in short the numbers are -2 and -4



4 0
3 years ago
Miles wanted to spend his allowance on computer games. He saved $65.00. How many games could he buy if each game costs $17.99
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8 0
3 years ago
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Verification of the True Statement:

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Let us take a number 3/5, this is a fraction.

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7 0
1 year ago
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Answer:

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Step-by-step explanation:

6 0
3 years ago
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8 0
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