Question

1. A 1.6 kg lab cart accelerates from 0.5 m/s to 4.3 m/s in 0.8 seconds.

Answer 1

Answer:

(a) 4.75 m/s²  (b) 7.6 N

Explanation:

Given that,

The mass of a lab cart, m = 1.6 kg

Initial speed, u = 0.5 m/s

Final speed, v = 4.3 m/s

Time, t = 0.8 s

(a) The acceleration of an object is equal to the rate of change of velocity. It can be calculated as :

$a=\dfrac{v-u}{t}\\\\a=\dfrac{4.3-0.5}{0.8}\\\\a=4.75\ m/s^2$

(b) Let F be the net force on the cart. It can be given by :

F = ma

$F=1.6\times 4.75\\\\F=7.6\ N$

Hence, this is the required solution.