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Mumz [18]
3 years ago
7

What happens to the glucose molecule during the process of cellular respiration?

Chemistry
2 answers:
Alex787 [66]3 years ago
8 0

The answer is A. It gets broken down.

Eduardwww [97]3 years ago
5 0

Answer:

<em>it's broken down into  carbon dioxide and water </em>

Explanation:

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kicyunya [14]
<span>copper(II) chloride octahydrate</span>
4 0
3 years ago
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Will these changes increase, decrease, or have no effect on the mean free path of the molecules in a gas sample?
lisabon 2012 [21]
According to the kinetic theory, the mean free path is the average distance a single atom or molecule of an element or compound travels with respect with the other atoms during a collision. The greater the mean free path, the more ideal the behavior of a gas molecule is because intermolecular forces are minimum. To understand which factors affect the mean free path, the equation is written below.

l = μ/P * √(πkT/2m), where
l is the mean free path
μ is the viscosity of the fluid
P is the pressure
k is the Boltzmann's constant
T is the absolute temperature
m is the molar mass

So, here are the general effects of the factors on the mean free path:

Mean free path increases when:
1. The fluid is viscous (↑μ)
2. At low pressures (↓P)
3. At high temperatures (↑T)
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The opposite is also true for when the mean free path decreases. Factors that are not found here have little or no effect.
6 0
4 years ago
A chemist working as a safety inspector finds an unmarked bottle in a lab cabinet. A note on the door of the cabinet says the ca
MrRa [10]

Answer:

1. density = 0.89 g/cm3

2. Yes is possible to identify the liquid

3. ethanolamine

Explanation:

<u>Data:</u>

mass = 682 g

volume = 0.767 L = 767 mL or cm3

1.

To calculate the density of the liquid it is necessary to know that the density formula is:

density=\frac{mass(g)}{volume(cm^{3}) }

The data obtained is replaced in the formula:

density=\frac{682g)}{767(cm^{3}) }=0.89\frac{g}{cm^{3} }

2.

With the given data it is possible to identify the liquid, this because the density value is a basic property of each liquid.

3.

It is possible to determine what liquid it is, since when comparing the value obtained with those reported in the collection of Material Safety Data Sheets (MSOS), the value that agrees is that of ethanolamine.

6 0
4 years ago
Suppose you were calibrating a 50.0 ml volumetric flask using distilled water. the flask temperature was at 20°c, and you assume
julsineya [31]
Density is sensitive to temperature for gases and liquids, although not much for liquids. We use the data in the picture. Using linear interpolation, we determine the densities at 14°C and 20°C.

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@14°C:
(10 - 14)/(10 - 20) = (0.99973 - Density)/(0.99973 - 0.99823)
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5 0
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What would be the shape of a molecule with triple bond?
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3 years ago
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