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3 years ago

What happens to the glucose molecule during the process of cellular respiration?

Chemistry

2 answers:

Alex787 [66]3 years ago

8 0

The answer is A. It gets broken down.

Eduardwww [97]3 years ago

5 0

Answer:

<em>it's broken down into carbon dioxide and water </em>

Explanation:

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Why do we use balanced equations ?

polet [3.4K]

Answer:

Balanced equations are used to allow chemists to calculate how much product they will produce from their reactants. The co-efficients in balanced equations represent the number of moles reacting and being produced, it is rare that this exact ratio will be used in a reaction.

Explanation:

8 0

3 years ago

Se disuelven 10 g de acido carbónico H2CO3 en 150 g de agua. Determina la concentración % m/m de esa disolución?

sergey [27]

The question is: 10 g of carbonic acid H2CO3 are dissolved in 150 g of water. Determine the% m / m concentration of that solution?

Answer: The% m / m concentration of that solution is 6.66%.

Explanation:

Given: Mass of solute = 10 g

Mass of solvent = 150 g

Formula used to calculate the %m/m is as follows.

$Percent (m/m) = \frac{mass of solute}{mass of solvent} \times 100$

Substitute the values into above formula as follows.

$Percent (m/m) = \frac{mass of solute}{mass of solvent} \times 100\\= \frac{10 g}{150 g} \times 100\\= 6.66%$

Thus, we can conclude that the% m / m concentration of that solution is 6.66%.

6 0

3 years ago

How many grams are there in 2.7 x 1021 molecules of NiNz?

Inessa05 [86]

Answer:

2.7 x 1021=2756.7

Explanation:

I don't know what NiNz is

3 0

3 years ago

Consider the following reaction:

djverab [1.8K]

<span>Kc = [H2S]²*[O2]³ / [H2O]²*[SO2]²
Let x be the moles of H2S formed. Each mole of H2S takes one each mole of H2O and SO2 so after the reactions
[H2O] = 2.8 - x and [SO2] = 2.6 - x also for each mole of H2S, 1.5 moles of O2 are formed, so [O2] = 1.5*x
Kc = x²*(1.5*x)³ / (2.8 - x)²*(2.6 - x)²
Thus use 2.8 - x = 2.8 and 2.6 - x = 2.6 in the above equation for Kc:
Kc = x²*(1.5*x)³ / 2.8²*2.6² = 3.375x^5 / 2.8²*2.6² = 0.06368*x^5
x^5 = 1.3*10^-6 / 0.06368 = 2.0414*10^-5
x = 0.115M </span> hope it helps

4 0

3 years ago

You are given a 2.9237 g sample of a substance with the generic formula MCl2(H2O)6. After completely drying the sample (which me

Katyanochek1 [597]

Answer:

M is cobalt (Co)

Explanation:

Step 1: Data given

Mass of MCl2(H2O)6 = 2.9237 grams

After completely drying the sample (which means removing the 6 moles of H2O per mole of MCl2), the sample weighs 1.5941 g.

Step 2: Calculate mass of water

Mass of water = 2.9237 - 1.5941 = 1.3296 grams

Step 3: Calculate moles water

Moles water = mass water / molar mass water

Moles water = 1.3296 grams / 18.02 g/mol

Moles water = 0.07378 moles

Step 4: Calculate moles of the whole substance

For 1 mol MCl2(H2O)6 we have 6 moles H2O

Number of moles of the whole substance = 0.07378 / 6 = 0.01230 moles

Step 5: Calculate molar weight of the substance

Molar weight = mass / moles

Molar weight = 1.5941 grams / 0.01230 moles

Molar weight = 129.6 g/mol

Step 6: Calculate molar weight of M

Molecular weight of M = 129.6 - (2*35.45)

Molecular weight of M = 58.7 g/mol

M is cobalt (Co)

4 0

3 years ago