Answer: None of these rabbits listed. they are all different species
Explanation:
I got it right on usatestprep
Answer:
True
Explanation:
<em>Please tell me if it is wrong!</em>
<em />
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The atomic symbol that could represent an isotope that undergoes radioactive decay to produce Pb-206 would be 238/92 U.
Answer:
<span>When identical particles pack in a simple cubic lattice, there is ONE particle per unit cell.
Explanation:
As we know that simple cube has eight corners and each particle at every corner is shared by eight cubic crystals. So it means that only </span><span>eighth </span>part of a particle is present at one corner of each cube. Therefore, each corner contain 1/8 particle, then all corners will contain 1/8 × 8 = 1 particle.
Answer:
Explanation:
From the information given:
Mass of carbon tetrachloride = 5 kg
Pressure = 1 bar
The given density for carbon tetrachloride = 1590 kg/m³
The specific heat of carbon tetrachloride = 0.84 kJ/kg K
From the composition, the initial volume of carbon tetrachloride will be:![= \dfrac{5 \ kg }{1590 \ kg/m^3}](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7B5%20%5C%20kg%20%7D%7B1590%20%5C%20kg%2Fm%5E3%7D)
= 0.0031 m³
Suppose
is independent of temperature while pressure is constant;
Then:
The change in volume can be expressed as:
![\int ^{V_2}_{V_1} \dfrac{dV}{V} =\int ^{T_2}_{T_1} \beta dT](https://tex.z-dn.net/?f=%5Cint%20%5E%7BV_2%7D_%7BV_1%7D%20%5Cdfrac%7BdV%7D%7BV%7D%20%3D%5Cint%20%5E%7BT_2%7D_%7BT_1%7D%20%5Cbeta%20dT)
![In ( \dfrac{V_2}{V_1}) = \beta (T_2-T_1)](https://tex.z-dn.net/?f=In%20%28%20%5Cdfrac%7BV_2%7D%7BV_1%7D%29%20%20%3D%20%5Cbeta%20%28T_2-T_1%29)
![V_2 = V_1 \times exp (\beta (T_2-T_1))](https://tex.z-dn.net/?f=V_2%20%3D%20V_1%20%5Ctimes%20exp%20%28%5Cbeta%20%28T_2-T_1%29%29)
![V_2 = 0.0031 \ m^3 \times exp (1.2 \times 10^{-3} \times 20)](https://tex.z-dn.net/?f=V_2%20%3D%200.0031%20%5C%20m%5E3%20%20%5Ctimes%20exp%20%20%281.2%20%5Ctimes%2010%5E%7B-3%7D%20%5Ctimes%2020%29)
![V_2 = 0.003175 \ m^3](https://tex.z-dn.net/?f=V_2%20%3D%200.003175%20%5C%20m%5E3)
However; the workdone = -PdV
![W = -1.01 \times 10^5 \ Pa \times ( 0.003175 m^3 - 0.0031 \ m^3)](https://tex.z-dn.net/?f=W%20%3D%20-1.01%20%5Ctimes%2010%5E5%20%5C%20Pa%20%5Ctimes%20%28%200.003175%20m%5E3%20-%200.0031%20%5C%20m%5E3%29)
W = - 7.6 J
The heat energy Q = Δ h
![Q = mC_p(T_2-T_1)](https://tex.z-dn.net/?f=Q%20%3D%20mC_p%28T_2-T_1%29)
![Q = 5 kg \times 0.84 \ kJ/kg^0 C \times 20](https://tex.z-dn.net/?f=Q%20%3D%205%20kg%20%5Ctimes%200.84%20%5C%20kJ%2Fkg%5E0%20C%20%5Ctimes%2020)
Q = 84 kJ
The internal energy is calculated by using the 1st law of thermodynamics; which can be expressed as;
ΔU = ΔQ + W
ΔU = 84 kJ + ( -7.6 × 10⁻³ kJ)
ΔU = 83.992 kJ