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Aneli [31]
2 years ago
6

Write the balanced chemical equation between H2SO4 and KOH in aqueous solution. This is called a neutralization reaction and wil

l produce whater and potassium sulfate. Phases are optional.
0.650 L of 0.430 M H2SO4 is mixed with 0.600 L of 0.240 M KOH. What concentration of sulfuric acid remains after neutralization?
Chemistry
1 answer:
emmainna [20.7K]2 years ago
7 0

Answer:

0.166M

Explanation:

In a neutralization, the acid, H₂SO₄, reacts with a base, KOH, to produce a salt, K₂SO₄ and water. The reaction is:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

To solve this problem, we need to determine moles of H2SO4 and moles of KOH that reacts to find the moles of sulfuric acid that remains after the reaction:

<em>Moles H2SO4:</em>

0.650L * (0.430mol /L) = 0.2795moles H2SO4

<em>Moles KOH:</em>

0.600L * (0.240mol / L) = 0.144 moles KOH

Moles of sulfuric acid that reacts with 0.144 moles of KOH are:

0.144 moles KOH * (1mol H2SO4 / 2 mol KOH) = 0.072 moles of H2SO4 react.

And remain:

0.2795moles H2SO4 - 0.072moles H2SO4 = 0.2075 moles of H2SO4 reamains.

In 0.650L + 0.600L = 1.25L:

Molar concentration of sulfuric acid:

0.2075 moles of H2SO4 / 1.25L =

<h3>0.166M</h3>
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A mixture in which particles are not evenly distributed and particles keep their unique properties are called as heterogeneous mixture.

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On a hot summer day you and some friends decide you want to cool down your pool. Determine the mass of ice you would need to add
sergeinik [125]

Answer: The mass of ice you would need to add to bring the equilibrium temperature of the system to 300 K is 16.14 \times 10^{4} kg.

Explanation:

We know that relation between heat energy and specific heat is as follows.

                 q = m \times S \times \Delta T

As density of water is 1 kg/L and volume is given as 400,000 L. Therefore, mass of water is as follows.

          Mass of water = Volume × Density

                                  = 400,000 L \times 1 kg/L

                                  = 400,000 kg

or,                              = 400,000 \times 10^{3} g    (as 1 kg = 1000 g)

Specific heat of water is 4.2 J/gm K. Therefore, change in temperature is as follows.

         \Delta T = 305 K - 273 K

                    = 32 K

Now, putting the given values into the above formula and calculate the heat energy as follows.

            q = m \times S \times \Delta T

                = 400,000 \times 10^{3} \times 4.2 \times 32 K

                = 5376 \times 10^{7} J

or,            = 5376 \times 10^{4} kJ

According to the enthalpy of melting of ice 333 kJ/Kg of energy absorbed by by 1 kg of ice. Hence, mass required to absorb energy of 5376 \times 10^{4} kJ  is calculated as follows.

            Mass = \frac{5376 \times 10^{4} kJ}{333 kJ/Kg} \times 1 kg

                      = 16.14 \times 10^{4} kg

Thus, we can conclude that the mass of ice you would need to add to bring the equilibrium temperature of the system to 300 K is 16.14 \times 10^{4} kg.

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HELP ASAP Will Give Brainlist
a_sh-v [17]

The correct answer is actually

D. requires a lot of energy to become hot.

As the definition of specific heat is "the heat required to raise the temperature of the unit mass of a given substance by a given amount."

3 0
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