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Andrews [41]
3 years ago
9

5. To increase this characteristic of contentment in my life, I need to...

Physics
1 answer:
Anon25 [30]3 years ago
4 0

Answer:

Love yourself, that's what you need to do. In order to be content, let yourself! Treat you right.

You might be interested in
If a 15 N box is lifted a distance of 3 m, how much work is done?
Naily [24]

Answer:

W=45J

Explanation:

W=Fd

W=15(3)=45

W=45J

7 0
3 years ago
Read 2 more answers
What is the fundamental unit for measuring mass in the metric system ?
goldenfox [79]
Kilogram(kg)
It's not the SI unit of mass in the metric system however.
6 0
3 years ago
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6) A boat crosses a river at a constant engine speed of 2.0 m/s under pointed Directly west. The river runs directly south at 2.
TEA [102]

Answer:ligma ;)

Explanation:

8 0
2 years ago
When water vapor rises into the atmosphere and begins to condense, it releases ________, the energy of a thunderstorm.
zubka84 [21]
The answer is latent heat. The specific latent heat of vaporisation, L_v, of a substance is the energy input required for each kilogram to be converted from liquid to gas by evaporation. The 'specific' means per kilogram, so more generally latent heat of vaporisation is the energy taken in during the process for a given mass.

Here we are not vaporising the substance. We are in fact condensing it, the reverse process. All this means is the latent heat is released as electrostatic potential decreases in the water, as opposed to being absorbed. I hope this helps you :)
5 0
3 years ago
Read 2 more answers
On a snowy day, max (mass = 15 kg) pulls his little sister maya in a sled (combined mass = 20 kg) through the slippery snow. max
sesenic [268]

Work done by a given force is given by

W = F.d

here on sled two forces will do work

1. Applied force by Max

2. Frictional force due to ground

Now by force diagram of sled we can see the angle of force and displacement

work done by Max = W_1 = Fdcos\theta

W_1 = 12*5cos15

W_1 = 57.96 J

Now similarly work done by frictional force

W_2 = Fdcos\theta

W_2 = 4*5cos180

W_2= -20 J

Now total work done on sled

W_{net}= W_1 + W2

W_{net} = 57.96 - 20 = 37.96 J

7 0
3 years ago
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