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3 years ago

How to write a balanced nuclear equation on how uranium can disintegrate to Actium

Chemistry

1 answer:

andrey2020 [161]3 years ago

5 0

Answer:

Balancing Nuclear Equations

To balance a nuclear equation, the mass number and atomic numbers of all particles on either side of the arrow must be equal.

Explanation:

follows:

→

To balance the equation above for mass, charge, and mass number, the second nucleus on the right side must have atomic number 2 and mass number 4; it is therefore also helium-4. The complete equation therefore reads:

→

Or, more simply:

→

image

Lithium-6 plus deuterium gives two helium-4s.: The visual representation of the equation we used as an example.

Compact

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An exhaled air bubble underwater at 290.

Vinil7 [7]

The answer for the following problem is mentioned below.

<u><em>Therefore the final volume of the gas is 52.7 ml.</em></u>

Explanation:

Given:

Initial pressure ( $P_{1}$ ) = 290 kPa

Final pressure ( $P_{2}$ ) = 104 kPa

Initial volume ( $V_{1}$ ) = 18.9 ml

To find:

Final volume ( $V_{2}$ )

We know;

From the ideal gas equation;

P × V = n × R × T

where;

P represents the pressure of the gas

V represents the volume of gas

n represents the no of the moles

R represents the universal gas constant

T represents the temperature of the gas

So;

P × V = constant

P ∝ $\frac{1}{V}$

From the above equation;

$\frac{P_{1} }{P_{2} } = \frac{V_{2} }{V_{1} }$

$P_{1}$ represents the initial pressure of the gas

$P_{2}$ represents the final pressure of the gas

$V_{1}$ represents the initial volume of the gas

$V_{2}$ represents the final volume of the gas

Substituting the values of the above equation;

$\frac{290}{104}$ = $\frac{V_{2} }{18.9}$

$V_{2}$ = 52.7 ml

<u><em>Therefore the final volume of the gas is 52.7 ml.</em></u>

6 0

3 years ago

Please help me with this! I'd appreciate it. Thanks so much! :D

Setler [38]

Answer:

It is the second option.

Explanation:

The conversion factor is:

I kPa = 7.50062 Torr.

3 0

3 years ago

V2 = (P1 × V1 × T2) (P2 × T1) A gas with a beginning pressure of 2 atm at a temperature of 300 K has a volume of 20 ml. What wil

rusak2 [61]

6.6ml will be the new volume if the pressure increases to 4 atm and the temperature are lowered to 200 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given data:

$V_1=20 ml$