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Andru [333]
3 years ago
7

One end of a string 6.26 m long is moved up and down with simple harmonic motion at a frequency of 95 Hz . The waves reach the o

ther end of the string in 0.5 s. Find the wavelength of the waves on the string. Answer in units of cm.
Physics
1 answer:
uranmaximum [27]3 years ago
4 0

Answer:

Explanation:

Given

length of string L=6.26\ m

frequency f=95\ Hz

time taken by wave to reach at other end t=0.5\ s

speed of  wave is given by

v=\frac{length\ of\ string}{time\ taken}

v=\frac{6.26}{0.5}

v=12.52\ m/s

wavelength of is given by

\lambda =\frac{velocity}{frequency}

\lambda =\frac{12.52}{95}

\lambda =0.131\ m                          

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Why is alpha rays not suitable to scan baggage at the airport?​
Inga [223]

Answer:

Alpha particles are not used to check baggage in airport as these rays are not penetrated far through matter.

<u>Explanation: </u>

Alpha particles are produced by the <em>decay of a radioactive nucleus.</em> These alpha rays are <em>ceased by paper</em>. The <em>nucleus</em> of the helium atom is made up of <em>two protons and two neutrons</em> is the particle <em>ejected by alpha particle</em>.

As helium is <em>harmless and as an inert gas</em>, so these particles are not dangerous in themselves. The airport baggage security uses only X-ray scanners to inspect. These rays identify the <em>hidden items inside the baggage. </em>

4 0
3 years ago
A horizontal force of 200 n is applied to move a 55-kg cart (initially at rest) across a 10-m level surface. what is the final k
Vesnalui [34]
<span>Kinetic energy is the energy that is possessed by an object that is moving. It is calculated by one-half the product of the mass and the square of the velocity of the object. We need to determine the velocity of the cart that is moving. 
</span>
First, we use Newton's Second Law of motion;
<span>Force = ma 
200 = 55a 
a = 3.64 m/s^2 

Then, from the kinematic equation we calculate the velocity;
v^2 = v0^2 + 2ax

where v is the final velocity, v0 is the initial veocity (zero since it initially start at zero), a is the acceleration ( 3.64 m/s^2) and x is the distance traveled.

v^2 = 0^2 + 2 (3.64) (10) 
v^2 = 72.73 m^2 / s^2
v = 8.53 m / s 

KE = mv^2 / 2
KE = 1/2 (55) (8.53^2) 
KE= 2000 J</span>
7 0
3 years ago
WILL UPVOTE!!!Physics help please!!
liubo4ka [24]
Speed v = initial speed u + acceleration a x time t 
v=u+at = 2 + 4*3 = 14 m/s

8 0
3 years ago
What are the answers to these 15 questions?
Dennis_Churaev [7]
(1) The skull consists of twenty-two bones. 
8 0
4 years ago
Find the ratio of the diameter of aluminium to copper wire, if they have the same
kicyunya [14]

Answer:

1.24

Explanation:

The resistivity of copper\rho_1=2.65\times 10^{-8}\ \Omega-m

The resistivity of Aluminum,\rho_2=1.72\times 10^{-8}\ \Omega-m

The wires have same resistance per unit length.

The resistance of a wire is given by :

R=\rho \dfrac{l}{A}\\\\R=\rho \dfrac{l}{\pi (\dfrac{d}{2})^2}\\\\\dfrac{R}{l}=\rho \dfrac{1}{\pi (\dfrac{d}{2})^2}

According to given condition,

\rho_1 \dfrac{1}{\pi (\dfrac{d_1}{2})^2}=\rho_2 \dfrac{1}{\pi (\dfrac{d_2}{2})^2}\\\\\rho_1 \dfrac{1}{{d_1}^2}=\rho_2 \dfrac{1}{{d_2}^2}\\\\(\dfrac{d_2}{d_1})^2=\dfrac{\rho_1}{\rho_2}\\\\\dfrac{d_2}{d_1}=\sqrt{\dfrac{\rho_1}{\rho_2}}\\\\\dfrac{d_2}{d_1}=\sqrt{\dfrac{2.65\times 10^{-8}}{1.72\times 10^{-8}}}\\\\=1.24

So, the required ratio of the diameter of Aluminum to Copper wire is 1.24.

3 0
3 years ago
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