Answer:
Here,
Initial velocity(u)=0 m/s
acceleration(a)=1.5m/s
time(t)=0.5s
Now,
distance covered(s)=ut+(1/2)at^2
=0*0.5+(1/2)*1.5*0.5*0.5
=0+(1/2)*0.375
=0+0.1875
=0.1875(nearly 0.19)
Hence,0.19 is correct answer.
<h3><u>Answer;</u></h3>
<u>An increase in pressure favors the formation of ozone </u>
<h3><u>Explanation;</u></h3>
- Ozone, O3, decomposes to molecular oxygen in the stratosphere according to the reaction
2O3(g) ⇆ 3O2 (g).
- There are more moles of product gas than moles of reactant gas. An increase in total pressure increases the partial pressure of each gas, shifting the equilibrium towards the reactants.
- Therefore; an increase in pressure favors backward reactions towards the formation of ozone.
The 102N acting on the ropes being pulled by eric and kim have some of that force acting horizontally, and some of it vertically. By visualizing it as a right angled triangle, with the hypotenuse the length of the diagonal force, and each side the length of the horizontal and vertical forces, you can use trigonometry to calculate the length of the vertical force. You are told that it is at an angle of 30 with the vertical rope, therefore you know the length of the hypotenuse, and the angle between it and the vertical force, so using trig: (vertical force=x)
x/102=cos(30)
x=102*cos(30)
x=88.33
Therefore the diagonal ropes give a vertical force of 88.33N, and the centre rope, as it acts vertically, gives a vertical force of all 102N. The total:
88.33*2+102=278.66N
I don't know if this is very clear, I hope its good enough to help. If you don't understand, just ask, and I can answer any questions!!! :)
Answer:
a) 2.02 years
b) 8.1 x 10⁻⁸.
Explanation:
Time period of a rotating body T² is proportional to radius of orbit R³ So
T₁² / T₂² = R₁³ /R₂³ ( T₁ and R₁ is time period and radius of orbit of the earth .)
1² / T₂² =( 1/1.6)³
T₂ = 2.02 years.
Kinetic energy of an orbiting body = 1/2 m v₀² ( v₀ is orbital speed)
= 1/2 m x 2 g R = m x G m/R² X R= m² x G /R
Kinetic energy of asteroid K₁ / kinetic energy of earth K₂ =
(mass of asteroid/mass of earth)² x( radius of earth / radius of asteroid)
=( 3.6 x 10⁻⁴)² x 1/1.6 = 8.1 x 10⁻⁸ .
