4 years ago

Help me solve this problem

1 answer:

7 0

27) Velocity and time
28) it indicates increasing velocity
29) It is moving in constant velocity which means no acceleration.

You might be interested in

A rope of negligible mass is wrapped around a 225-kg solid cylinder of radius 0.400 m. the cylinder is suspended several meters

emmainna [20.7K]

Let me know if you have questions

5 0

3 years ago

A gas at constant temperature is confined to a cylinder with a movable piston. The piston is slowly pushed into the cylinder, de

Inessa [10]

C. Volume and pressure
Key words: increases and decreases

4 0

3 years ago

Read 2 more answers

The deflection of alpha particles in rutherford’s gold foil experiments resulted in what change to the atomic model? the additio

skelet666 [1.2K]

The answer is: The addition of a small dense nucleus at the center of the atom.

5 0

3 years ago

Read 2 more answers

Sir Percival and his horse are standing still on a field of honor when Sir Rodney, atop his steed gallops by with a constant vel

Ludmilka [50]

Answer:

d. none of these

Explanation:

From the given information:

Let assume that Percival catches Sir Rodney's horse in time "t" after covering a certain distance "s"

Then, using the second equation of motion:

$S = ut + \dfrac{1}{2}at^2$

FOR Percival, we have:

$S = (0\times t ) + \dfrac{1}{2} \times 0.6 \ m/s \times t^2 \\ \\ S = 0.3 \ m/s \times t^2 -- -- (1)$

FOR Sir Rodney;

$S = ut + \dfrac{1}{2}at^2$

$S = (3\times t ) + \dfrac{1}{2} \times 0 \times t^2 \\ \\ S =3t--- (2)$

Equating both equations together; we have:

0.3t² = 3t

0.3t² - 3t = 0

0.3t(t - 10) = 0

If Percival's position at rest = 0

Then; t = 10 s.

8 0

3 years ago

Quiz Review Problems

zlopas [31]

The momentum of a neutron p = 586.25 kg m / s.

<u>Explanation:</u>

The product of mass and the velocity gives the momentum of an object and it is a vector quantity. It is denoted by the letter p. The unit of momentum is kilogram meter per second (or) kg m / s.

Given mass m = 1.675 $\times$ 10, velocity v = 3.500 $\times$ 10

Momentum, p = mv

where m represents the mass,

v represents the velocity.

momentum p = (1.675 $\times$ 10) $\times$ (3.500 $\times$ 10)

momentum p = 586.25 kg m / s.

5 0

3 years ago