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Serhud [2]
3 years ago
11

Mole Conversion??????

Chemistry
1 answer:
aniked [119]3 years ago
3 0

Answer:

d

Explanation:

so in this question we need to find how many moles of H2O could be formed from 3.5 moles of oxygen.

And we know that 6 moles of H2O would be formed from 8 moles of O2 from this reaction.

By using stoichiometry we can find how many moles of H2O could be formed from 3.5 moles of oxygen since the ratio between O2 and H2O will not change even if we change the initial value of the reactants

3.50 moles of O2 * ((6 moles H2O)/(8 moles of O2))

which is d

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Calculate the percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl on the assumption that t
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Answer:

1.089%

Explanation:

From;

ν =1/2πc(k/meff)^1/2

Where;

ν = wave number

meff = reduced mass or effective mass

k = force constant

c= speed of light

Let

ν =1/2πc (k/meff)^1/2  vibrational wave number for 23Na35 Cl

ν' =1/2πc(k'/m'eff)^1/2 vibrational wave number for 23Na37 Cl

The between the two is obtained from;

ν' - ν /ν  = (k'/m'eff)^1/2 - (k/meff)^1/2 / (k/meff)^1/2

Therefore;

ν' - ν /ν = [meff/m'eff]^1/2 - 1

Substituting values, we have;

ν' - ν /ν = [(22.9898 * 34.9688/22.9898 + 34.9688) * (22.9898 + 36.9651/22.9898 * 36.9651)]^1/2  -1

ν' - ν /ν = -0.01089

percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl;

ν' - ν /ν * 100

|(-0.01089)|  × 100 = 1.089%

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