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3 years ago

50.00 ml of nitric acid (of unknown

Chemistry

1 answer:

mr Goodwill [35]3 years ago

5 0

Answer:

A)HNO_3 + NaOH → NaNO_3 + H2O

B) Explained below

C)volume of NaOH at the equivalence point will simply be the volume added to reach a pH value of 7.

D)the pH at the equivalence point is 7.

E)C(HNO3) = 0.1 × (volume of NaOH at equivalence point)/50

Explanation:

A) A symbolic equation for the reaction is;

HNO_3 + NaOH → NaNO_3 + H2O

B) HNO3 is a strong acid and NaOH is a strong base and as such they will both dissociate almost fully in a water solution to form ions. Thus, the reaction equation can now be rewritten in form of:

H(+) + OH(-) → H2O

From this reaction equation, it's clear that when sodium hydroxide (NaOH) was added, the positive hydrogen ions (H+) react with the negative hydroxyl ions (OH-) to form water (H2O).

Thus, the concentration [H+] will decrease because of both dilution and the decreasing amount of positive hydrogen ions (H+) in the solution. From definition, the pH is given by the formula;

pH = −log[H+]

Thus, pH increases as NaOH is added to HNO3 as given in the question.

C) The volume of NaOH at the equivalence point will simply be the volume added to reach a pH value of 7.

D) Since the given acid and base are very strong, it means that the solution at equivalence point is likely to be neutral. Thus, the pH at the equivalence point is 7.

E) Concentration of the nitric acid solution is given by;

C(HNO3) = (volume of NaOH at equivalence point × concentration of NaOH)/(volume of HNO3)

We are given;

concentration of NaOH) = 0.1 mol/L

Volume of HNO3 = 50 mL

Thus;

C(HNO3) = 0.1 × (volume of NaOH at equivalence point)/50

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Is HF the most polar among covalent bonds?

Sladkaya [172]

Answer:

No.

Explanation:

HI is more polar than HF

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2 years ago

Formula los siguientes compuesto: Dietil eter, Etanol, Propanotriol, Acido Propanodioico, Pentanal, Pentano-2,4-diona, Metanoato

9966 [12]

Answer:

Explanation:

En este caso para formular los compuestos, debes identificar el grupo funcional principal de la molecula. Una vez que eso está hecho, puedes intentar formularlo.

Empezaremos primero identificando el grupo funcional principal de la molécula, para luego formularlo correctamente.

Dietil eter: la terminación eter al final significa que pertenece al grupo de los éteres, el cual tiene como formula general R - O - R.

Etanol: debido a que termina en ol, este grupo pertenece a los alcoholes. Para formularlo solo se dibuja la molecula del etano, junto a un enlace con el grupo OH, como su formula general R - OH.

Propanotriol: igualmente termina en ol, por lo tanto es un alcohol, sin embargo, en este caso, tambien tiene la terminación prefija tri, asi que significa que hay 3 grupos OH en la molecula.

Acido propanodioico: esta es sencilla, porque empieza como acido, y solo hay un grupo funcional que empieza así y son los acidos carboxilicos, es decir, el grupo COOH (R - COOH) que es el carboxilo. Tiene el prefijo di, antes del oico, por lo que son dos carboxilos presentes en la molecula.

Pentanal: el sufijo al, significa que pertenece al grupo de los aldehidos, en este caso, posee el grupo carbonilo H - C = O.

Pentano - 2,4 - diona: la terminación ona significa que pertenece al grupo de las cetonas, (R - CO - R), parecido a los aldehidos, con la diferencia de que tiene grupos alquilos en lugar de un hidrogeno.

Metanoato de metilo: la terminación ato de ilo, pertenece a los esteres, (R - COOR) derivado de los acidos carboxilicos.

De aqui en adelante solo mencionaré los grupos funcionales pues ya se explicó el por que, por sus terminaciones:

Ciclohexano - 1.3 - diol: este pertenece a los alcoholes.

Acido heptanoico: acido carboxilico

Ciclobutil metil eter: eteres

Acetato de etilo: ester

2-metilbenzaldehído: aldehído unido a un grupo aromatico como el benceno.

Ciclohexanona: un ciclo (cadena cerrada) unido a un grupo carbonilo.

Butanona: cetona.

Observa la foto adjunta para que veas la formulación de cada una:

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3 years ago

Describes the three-dimensional arrangement of the atoms in a molecule states that two negatively charged particles (electrons)

Romashka [77]

Answer:

When atoms other than hydrogen form covalent bonds, an octet is accomplished by sharing. The octet rule can be used to explain the number of covalent bonds an atom forms. This number normally equals the number of electrons that atom needs to have a total of eight electrons (an octet) in its outer shell

Explanation:

chemistry, the octet rule explains how atoms of different elements combine to form molecules. ... In a chemical formula, the octet rule strongly governs the number of atoms for each element in a molecule; for example, calcium fluoride is CaF2 because two fluorine atoms and one calcium satisfy the rule.

octet rule: Atoms lose, gain, or share electrons in order to have a full valence shell of eight electrons. Hydrogen is an exception because it can hold a maximum of two electrons in its valence level.

There is another rule, called the duplet rule, that states that some elements can be stable with two electrons in their shell. Hydrogen and helium are special cases that do not follow the octet rule but the duplet rule. ... They are stable in a duplet state instead of an octet state.

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3 years ago

Reaction rate cannot increase once all enzyme ______________ are bound

Leviafan [203]

Answer:

reaction rate cannot increase once all enzyme active sites are bound

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3 years ago

To determine the ammonia concentration in a sample of lake water, three samples are prepared. In sample A, 10.0 mL of lake water

Masteriza [31]

Answer:Sample Absorbance (625 nm)

A 0.536

B 0.783

C 0.045

Therefore, I will use these data to solve your question. If you have other absorbances values, just follow my steps and plug in different numbers.

First, we see 1 mole of NH3 gives 1 mole product.

In B moles of NH3 = moles of NH3 in A + (5.5 x10^-4 x2.5/1000) = 1.375 x10^6 + mA

( mA = moles of NH3 in A) vol of B = 25 = vol of A

now A = el C = eC ( since l = 1cm)

Because, n net absorbance due to complex blank absorbance must be removed.

Here A(A) = 0.536 - 0.045 = 0.491 , A(B) = 0.783 - 0.045 = 0.738

(you can plug in different numbers in this step)

A2/A1 = C2/C1 , A(B)/A(A) = (1.375x10^-6 +mA)/(mA) = 0.738/0.491

So, mA = 2.733 x 10^-6 = moles of NH3 in A (Lake water)

Hence [NH3] water ( 2.733 x10^-6 ) x 1000/25 = 1.093 x 10^-4 M

Lake water vol = 10 ml out of 25,

Concentration of ammonia in lake water = 2.733 x10^-6 x 1000/10 = 2.733 x 10^-4 M

Then, A = 0.491 = e x 1 x 1.093 x10^-4

e = 4492 M-1cm-1

Explanation:

4 0

3 years ago