Ask question

Ask question

All categories

2 years ago

15

What is it that makes a magnet different from a piece of iron that is not mangetic?

1 answer:

Alisiya [41]2 years ago

7 0

Answer:

Under normal conditions, a magnetic material like iron doesn't behave like a magnet because the domains don't have a preferred direction of alignment. On the other hand, the domains of a magnet (or a magnetized iron) are all aligned in s specific direction.

You might be interested in

True or False: The more mass an object has, the faster it will fall.

Elza [17]

Answer:

True

Explanation:

8 0

3 years ago

Read 2 more answers

The maximum pressure achieved during ventricular contraction is called

Bezzdna [24]

Cardiovascular system

8 0

3 years ago

Read 2 more answers

Which is an example of observational learning?

vekshin1

Janice is the one who learned something by watching what was going on in the world around her.

8 0

3 years ago

Read 2 more answers

What is this?<br> Picture

miss Akunina [59]

Answer:

may be upside down alphabet :"T"

Explanation:

8 0

3 years ago

Read 2 more answers

slader Question: A Model Rocket Is Launched Straight Upward With An Initial Speed Of 50m/s. Iit Accelerates With A Constant Upwa

xenn [34]

Answer:

Maximum height reached by the rocket is

$y_{max} = 308 m$

total time of the motion of rocket is given as

$T = 16.44 s$

Explanation:

Initial speed of the rocket is given as

$v_i = 50 m/s$

acceleration of the rocket is given as

$a = 2 m/s^2$

engine stops at height h = 150 m

so the final speed of the rocket at this height is given as

$v_f^2 - v_i^2 = 2 a d$

$v_f^2 - 50^2 = 2(2)(150)$

$v_f = 55.68 m/s$

so maximum height reached by the rocket is given as the height where its final speed becomes zero

so we will have

$v_f^2 - v_i^2 = 2 a d$

$0 - 55.68^2 = 2(-9.81)(y - 150)$

$y_{max} = 308 m$

Now the total time of the motion of rocket is given as

1) time to reach the height of 150 m

$v_f - v_i = at$

$55.68 - 50 = 2 t$

$t_1 = 2.84 s$

2) time to reach ground from this height

$\Delta y = v_y t + \frac{1}{2}gt^2$

$-150 = 55.68 t - \frac{1}{2}(9.81) t^2$

$t_2 = 13.6 s$

so total time of the motion of rocket is given as

$T = 13.6 + 2.84 = 16.44 s$

3 0

3 years ago