Answer: 6.12 kg
Explanation:
Since Mass of ball = ? (let the unknown value be Z)
Acceleration due to gravity, g= 9.8m/s^2
Height, h = 1.5 metres
Gravitational potential energy GPE = 90J
Gravitational potential energy depends on the weight of the ball, the action of gravity and height.
Thus, GPE = Mass m x Acceleration due to gravity g x Height h
90J = Z x 9.8m/s^2 x 1.5m
90 = Z x 14.7
Z = 90/14.7
Z = 6.12 kg
Thus, the bowling ball weigh 6.12 kilograms
Given Information:
Angular displacement = θ = 51 cm = 0.51 m
Radius = 1.8 cm = 0.018 m
Initial angular velocity = ω₁ = 0 m/s
Angular acceleration = α = 10 rad/s
²
Required Information:
Final angular velocity = ω₂ = ?
Answer:
Final angular velocity = ω₂ = 21.6 rad/s
Explanation:
We know from the equations of kinematics,
ω₂² = ω₁² + 2αθ
Where ω₁ is the initial angular velocity that is zero since the toy was initially at rest, α is angular acceleration and θ is angular displacement.
ω₂² = (0)² + 2αθ
ω₂² = 2αθ
ω₂ = √(2αθ)
We know that the relation between angular displacement and arc length is given by
s = rθ
θ = s/r
θ = 0.51/0.018
θ = 23.33 radians
finally, final angular velocity is
ω₂ = √(2αθ)
ω₂ = √(2*10*23.33)
ω₂ = 21.6 rad/s
Therefore, the top will be rotating at 21.6 rad/s when the string is completely unwound.
The answer is the suns gravity
Answer:
dz = 7.136 (answer)
Explanation:
given height for kate's kite = 50 ft (say y)
due to drift it move towards east = dx = 7 ft
string maximum length = 107 ft ( say z)
we have to find change in z
that is dz
it will form a right angle triangle for x , y and z where x is base y is height and z is hypotenuse
so we get according to Pythagoras Theorem
...............(i)
by derivative both side consider y as constant
from (i) equation
now put the value and find dz
after solving these we get
dz = 7.136 (answer)
Answer:
1.) Putting club or the putter
2.) Either the 4-, 5-, or the 6- iron club
3.) 14 clubs
4.) The height of the golfer
Explanation:
I used to golf
