Answer:
he would have had read 9/12 of the book in total
Step-by-step explanation:
Answer:
Yes, Rolle's theorem can be applied
There is only one value of c such that f'(c) = 0, and this is c = 1.5 (or 3/2 in fraction form)
Step-by-step explanation:
Yes, Rolle's theorem can be applied on this function because the function is continuous in the closed interval (it is a polynomial function) and differentiable in the open interval, and f(a) = f(b) given that:

Then there must be a c in the open interval for which f'(c) =0
In order to find "c", we derive the function and evaluate it at "c", making the derivative equal zero, to solve for c:

There is a unique answer for c, and that is c = 1.5
Answer:
16x -2
Step-by-step explanation:
You know how to compute the perimeter of a rectangle of length L and width W:
P = 2(L+W)
Here, you're asked to use the given algebraic expressions for length and width and simplify the result of putting those in the perimeter formula.
P = 2((5x-2) +(3x+1))
P = 2(8x -1)
P = 16x -2 . . . the perimeter of the rectangle
Answer:
-539.25
Step-by-step explanation:
(w^2x−3)÷10⋅z
w=−9, x = 2.7, and z=−25
((-9)^2*2.7−3)÷10⋅(-25)
Parentheses first
The exponent in the parentheses
(81*2.7−3)÷10⋅(-25)
Then multiply
(218.7−3)÷10⋅(-25)
Then subtract
(215.7)÷10⋅(-25)
Now multiply and divide from left to right
21.57*(-25)
-539.25
Answer:
<em>The uniform rate of depreciation is $56,333 per year, or 11% per year.</em>
Step-by-step explanation:
<u>Rate of Depreciation</u>
If some object has a certain value P and after some time t its value decreases to Q, the rate of depreciation is a measure of how much its value changed per unit time.
It can be calculated as:

It can also be expressed as a percentage, dividing the previous value by P.
The school bus reduces its value from $512,000 to $343,000 in 3 years, thus:


R = 56,333 $/year
Expressed as a percentage:
R = 56,333 / 512,000 = 0.11
R = 11%/year
The uniform rate of depreciation is $56,333 per year, or 11% per year.