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iris [78.8K]
3 years ago
8

Which One Doesn't Belong?

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
7 0

Answer:

I THINK C I’m not totally sure because it has an end point visible

Step-by-step explanation:

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Give highly palatable and nutritious food.
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5 0
2 years ago
Solve for J MUST SHOW WORK<br> j/-2 + 7 = -12<br><br> thx!!
Ronch [10]

Answer:

j=38

Step-by-step explanation:

j/-2 +7=-12,  subtract 7 from both sides of the equation and you get j/-2 = -19, then you multiply j/-2 by -2/1  and multiply -19 by -2/1 to get j= 38

5 0
2 years ago
Reducing fraction 80/100
IceJOKER [234]

Answer:

4/5 is fully reduced


Step-by-step explanation:


4 0
3 years ago
Hi can you guys help me. The topic is similiar shapes in this case triangles do you guys know how to find a length. I got some p
Airida [17]

PR=18mm
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4 0
3 years ago
Find the derivative of Y=2xcos2x​
Nastasia [14]

Answer:

Y' = -xsin(2x) + 2cos(2x)

Step-by-step explanation:

For this problem, we will need to use the product rule since you have two terms that contain the variable x.

The product rule is simply as follows:

The derivative of the function is the product of the first term times the derivative of the second term plus the derivative of the first term times the second term.

Note the derivative of 2x with respect to x, is 2.

Note the derivative of cos(2x) with respect to x is (-1/2) sin(2x).

With this in mind, let's find the derivative of our function with respect to x.

Y = 2xcos2x

Y = 2x * cos(2x)

Y' = 2x * (-1/2)sin(2x) + 2 * cos(2x)

Y' = (2x * -1 / 2) sin(2x) + 2 * cos(2x)

Y' = (-x)sin(2x) + 2cos(2x)

So the derivative of our function is Y' = -xsin(2x) + 2cos(2x) according to the application of the product rule.

Cheers.

3 0
2 years ago
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