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3 years ago

9

Using the binding energy per nucleon number that you previously calculated for the isotope cobalt-60, is this a high amount of b

inding energy per nucleon according to the graph?

1 answer:

lora16 [44]3 years ago

6 0

Answer: yes

Explanation: I did this question before

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a light wave is traveling straight up out of the ocean then moves out into the air how do you expect the movement of the light w

Mariulka [41]

If the light is traveling straight up, then it hits the interface (surface
or boundary) between water and air perpendicularly (90° to the surface).

This direction is the direction of the 'normal' to the surface. So the
angle of incidence is zero, and that means the angle of refraction is
also zero. The light just keeps going in the same direction when it
emerges into the air, and is not bent.

However, its speed increases in air, and that means its wavelength
also becomes longer than it was in the water.

6 0

4 years ago

It has been claimed that an insect called the froghopper (Philaenus spumarius) is the best jumper in the animal kingdom. This in

Vladimir [108]

Answer:

v=4m/s

Explanation:

The formulas for accelerated motion are:

$v=v_0+at\\x=x_0+v_0t+\frac{at^2}{2}$

We can derive the formula $v^2=v_0^2+2ad$ from them.

We have:

$v-v_0=at\\t=\frac{v-v_0}{a}$

And substitute:

$x=x_0+v_0(\frac{v-v_0}{a})+\frac{a}{2}(\frac{v-v_0}{a})^2\\x-x_0=\frac{v_0(v-v_0)}{a}+\frac{(v-v_0)^2}{2a}\\2a(x-x_0)=2v_0(v-v_0)+(v-v_0)^2=2v_0v-2v_0^2+v^2+v_0^2-2vv_0=v^2-v_0^2$

Where in the first step of the last row we just multiplied everything by 2a. Since $x-x_0$ is the displacement d, we have proved that $v^2=v_0^2+2ad$

We use then our values to calculate the final velocity when starting from rest, traveling a distance 0.002m with acceleration $4000 m/s^2$ :

$v=\sqrt{v_0^2+2ad}=\sqrt{2(4000m/s^2)(0.002m)}=4m/s$

7 0

3 years ago

Define "increased productivity" in terms of the number of tasks and the amount of time.

vovikov84 [41]

Answer:

The greater the amount of output for a given unit of input, the higher the overall productivity. Businesses generally aim to improve productivity over time to maintain competitiveness and increase the business's profitability. Individuals are familiar with the idea of productivity in their own lives.

6 0

3 years ago

In the absence of a gravitational field, you could determine the mass of an object (of unknown composition) by:

lina2011 [118]

Answer:

A) By applying a known force, and measuring it's acceleration.

Explanation:

This is actually something that astronauts do in space as a mathmatical exercise when calculating the mass of an object since F = m × a.

Once the force, and acceleration are applied, the only unknown is the mass which can be solved by dividing force over acceleration. This is because inertial mass is equal to gravitational mass.

3 0

3 years ago

Si una bala de 122 g que viaja a 350 m/s golpea a un policía con chaleco antibalas el cual soporta 120 J de energía, ¿la bala at

Zanzabum

Answer:

Puesto que la energia cinética traslacional es mucho mayor que la capacidad del chaleco antibalas, la bala atravesaría el chaleco antibalas.

Explanation:

Un chaleco antibalas soporta el disparo de una bala disipando la energía de esta última a través de su propio material. Si sabemos que el chaleco antibalas soporta 120 joules de energía, cabe saber si la energía cinética traslacional es igual o inferior a ese límite, significando que la bala no atravesaría el chaleco.

La energía cinética traslacional de la bala ( $K$ ), in joules, queda expresada con la siguiente fórmula:

$K = \frac{1}{2}\cdot m\cdot v^{2}$ (1)

Donde:

$m$ - Masa de la bala, en kilogramos.

$v$ - Rapidez de la bala, en metros por segundo.

Si sabemos que $m = 0.122\,kg$ y $v = 350\,\frac{m}{s}$ , entonces la energía cinética traslacional de la bala es:

$K = 7472.5\,J$

Puesto que la energia cinética traslacional es mucho mayor que la capacidad del chaleco antibalas, la bala atravesaría el chaleco antibalas.

4 0

3 years ago