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3 years ago

9

Using the binding energy per nucleon number that you previously calculated for the isotope cobalt-60, is this a high amount of b

inding energy per nucleon according to the graph?

1 answer:

lora16 [44]3 years ago

6 0

Answer: yes

Explanation: I did this question before

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3. An astronaut on a space-walk swings a 0.5 kg metal tool in a circular path at the end of a cable 3.6 m long. The astronaut th

Semenov [28]

Answer:

Explanation:

2 km a hour

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3 years ago

Explain what effect losing a gamma ray has on a nucleus.

gogolik [260]

Answer:

Hi, Since energy levels in the nucleus are much higher than those in the gas, the nucleus will cool down by emitting a more energetic electromagnetic wave called a gamma ray . Gamma ray emission causes no change in the number of particles in the nucleus meaning both the atomic number and mass number remain the same.

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2 years ago

Monochromatic light of wavelength 385 nm is incident on a narrow slit. On a screen 3.00 m away, the distance between the second

LiRa [457]

To solve this problem it is necessary to apply the concepts related to the concept of overlap and constructive interference.

For this purpose we have that the constructive interference in waves can be expressed under the function

$a sin\theta = m\lambda$

Where

a = Width of the slit

d = Distance of slit to screen

m = Number of order which represent the number of repetition of the spectrum

$\theta =$ Angle between incident rays and scatter planes

At the same time the distance on the screen from the central point, would be

$sin\theta = \frac{y}{d}$

Where y = Represents the distance on the screen from the central point

PART A ) From the previous equation if we arrange to find the angle we have that

$\theta = sin^{-1}(\frac{y}{d})$

$\theta = sin^{-1}(\frac{1.4*10^{-2}}{3})$

$\theta = 0.2673\°$

PART B) Equation both equations we have

$a sin\theta = m\lambda$

$a \frac{y}{d} = m\lambda$

Re-arrange to find a,

$a = \frac{(2)(385*10^{-9})(3)}{(1.4*10^{-2})}$

$a = 1.65*10^{-4}m$

8 0

3 years ago

At the surface of Jupiter's moon Io, the acceleration due to gravity is 1.81 m/s2 . A watermelon has a weight of 54.0 N at the s

butalik [34]

Answer:

$m=5.51Kg$

Explanation:

The weight of an object on Earth is given by $W=mg$ , so we can calculate its mass by doing $m=W/g$ , which for our values is:

$m=(54N)/(9.8m/s^2)=5.51Kg$

<em>Nothing is being asked</em> about Io but if one wanted to know the weight <em>W'</em> of the watermelon there one just have to do:

$W'=ma=(5.51Kg)(1.81m/s^2)=9.97N$

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3 years ago

50 POINTS‼️‼️‼️‼️‼️

Inessa05 [86]

Answer:

Explanation:

the yellow box is -5

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3 years ago

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