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3 years ago

What are the steps and structures involved in the process of cellular respiration?

Physics

2 answers:

zhannawk [14.2K]3 years ago

8 0

Answer:

Cellular respiration is a metabolic pathway that breaks down glucose and produces ATP. The stages of cellular respiration include glycolysis, pyruvate oxidation, the citric acid or Krebs cycle, and oxidative phosphorylation.

Explanation:

Ber [7]3 years ago

4 0

Answer:

Cellular respiration takes in food and uses it to create ATP, a chemical which the cell uses for energy. Usually, this process uses oxygen, and is called aerobic respiration. It has four stages known as glycolysis, Link reaction, the Krebs cycle, and the electron transport chain

hope this helps

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Explanation:

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When she rides her bike, she gets to her first classroom building 36 minutes faster than when she walks. Of her average walking

postnew [5]

Answer:

$d=2.4\ miles$

Explanation:

Given:

average walking speed, $v_w=3\ mph$

average biking speed, $v_b=12\ mph$

<u>According to given condition:</u>

$t_w=t_b+\frac{36}{60}$

where:

$t_w=$ time taken to reach the building by walking

$t_b=$ time taken to reach the building by biking

We know that,

$\rm time=\frac{distance}{speed}$

so,

$\frac{d}{v_w} =\frac{d}{v_b} +\frac{36}{60}$

$\frac{d}{3}=\frac{d}{12} +\frac{3}{5}$

$d=2.4\ miles$

7 0

3 years ago

Read 2 more answers

A projectile is fired vertically from Earth's surface with

scoray [572]

Answer:

$h=25.52\times10^6 m$

Explanation:

Initial speed, v = 10 x 10^3 m/s

Mass of the earth, M = 6 x 10^24 kg

Radius of the earth, R = 6.4 x 10^6 m

Maximum from the surface of earth, h = ?

Let m = Mass of the projectile

Solution:

Potential energy at maximum height = ( Potential + Kinetic energy ) at the surface

$-G M m / ( R + h )=- G M m / R + (1/2) m v^2$

$- G M / ( R + h ) = - G M / R + (1/2) v^2$

$-2\times G M / ( R + h ) = ( - 2 G M / R ) + v^2$

$-2\times6.67\times10^{-11}\times6\times10^{24}/ ( R + h )$

= $( (- 2\times 6.67\times10^{-11}\times6\times10^{24}) /(6.4\times10^6)} +10000^2$

= $-2.50625\times10^7 J$

$=- 8\times10^{14} / ( R + h )=-2.50625\times 10^7$

$R+h=31.92\times10^{6}$

$h=31.92\times10^{6}-6.4\times10^6$

$h=25.52\times10^6 m$

5 0

3 years ago

During a circus performance, a 72-kg humancannonball is shot out of an 18-m-long cannon. If thehuman cannonball spends 0.95 s in

andreyandreev [35.5K]

Answer:

2872.8 N

Explanation:

We have the following information

m =n72kg

Δy = 18m

t = 0.95s.

From here we use the equation

Δy=1/2at2 in order to solve for the acceleration.

So a

=( 2x 18m)/(0.95s²)

= 36/0.9025

= 39.9m/s2.

From there we use the equation

F = ma

F=(72kg) x (39.9)

= 2872.8N.

2872.8N is the average net force exerted on him in the barrel of the cannon.

Thank you!

7 0

3 years ago

A plane flies along a straight line path after taking off, and it ends up 220 km farther east and 100.0 km farther north, relati

love history [14]

Answer:

North east

Explanation:

The distance travelled by a plane from one point to another is the shortest distance between the two points. This distance travelled is usually a straight line path from point 1 to point 2.

Since the plane ends up 220 km farther east and 100.0 km farther north, the direction of flight for the plane is in the North-East direction.

Let x represent the distance travelled by the plane. Hence:

x² = 100² + 220²

x² = 58400

x = 241.66 km

3 0

3 years ago

A machine can never be 100% efficient because some work is always lost due to .

klasskru [66]

Friction
Hope it helped

5 0

4 years ago

Read 2 more answers