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Art [367]
3 years ago
5

What are the steps and structures involved in the process of cellular respiration?

Physics
2 answers:
zhannawk [14.2K]3 years ago
8 0

Answer:

Cellular respiration is a metabolic pathway that breaks down glucose and produces ATP. The stages of cellular respiration include glycolysis, pyruvate oxidation, the citric acid or Krebs cycle, and oxidative phosphorylation.

Explanation:

Ber [7]3 years ago
4 0

Answer:

Cellular respiration takes in food and uses it to create ATP, a chemical which the cell uses for energy. Usually, this process uses oxygen, and is called aerobic respiration. It has four stages known as glycolysis, Link reaction, the Krebs cycle, and the electron transport chain

hope this helps

have a good day :)

Explanation:

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Which element listed would have the greatest electronegativity?
DiKsa [7]

Answer:

A. Fluorine

Explanation:

This is because it has the smallest atomic radius.

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7 0
3 years ago
Read 2 more answers
С
Lelechka [254]

Answer:

a = 0.8 [m/s²]

Explanation:

To solve this problem we must use Newton's second law which tells us that the resulting force on a body is equal to the product of mass by acceleration, in this way we come to the following equation:

∑F = m*a

where:

F = forces applied [N]

m = mass = 1000 [kg]

a = acceleration [m/s²]

Now using Newton's second law.

1200 - 400 = 1000*a\\800 = 1000 *a\\a=0.8[m/s^{2} ]

8 0
3 years ago
A cardinal (Richmondena cardinalis) of mass 4.00×10−2 kg and a baseball of mass 0.146 kg have the same kinetic energy. What is t
sp2606 [1]

Answer:

0.5232

Explanation:

the cardinal and the baseball has the same kinetic energy

\frac{1}{2} m_{c} v_{c} ^{2}  = \frac{1}{2} m_{b} v_{b} ^{2}

m_{c}v_{c}^{2} = m_{b}v_{b}^{2}

[4.0X 10^{-2} ]v_{c} ^{2} = [0.146]v_{b} ^{2}

\frac{v_{c} }{v_{b} } = \sqrt{\frac{0.146}{4.0 X 10^{-2} } }

\frac{v_{c} }{v_{b} } = 1.910

Ratio of momentum

\frac{p_{c}}{p_{b}}  = \frac{m_{c}v_{c}}{m_{b}v_{b}} = \frac{ (4.0 X 10^{-2} )(1.910v_{b} )}{0.146v_{b} }

\frac{p_{c}}{p_{b}} = \frac{4.0 X  10 ^{-2} X 1.910 }{0.146}  = 0.5232

6 0
4 years ago
How high would a projectile go if it was launched from ground level with an initial speed of 26 m/s at an angle of 30 degrees ab
tigry1 [53]

Answer:

Vy = 26 m/s sin 30 = 13 m/s      vertical speed

t = Vy / a = 13 m/s / 9.80 m/s^2 = 1.33 sec     time to reach Vy = 0

H = Vy t + 1/2 g t^2

H = 13 m/s * 1.33 sec - 1.33^2 * 9.8 / 2 m = 8.62 m

4 0
1 year ago
Ok so if atoms cant touch then why can the average human experience touch
djyliett [7]
While we think and feel that we are touching, we actually are not(: It’s all an illusion made by the brain
5 0
3 years ago
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