The second object, the one that had twice the force applied to it, would move twice as far, I believe.
Answer:
1752.14 tonnes per year.
Explanation:
To solve this exercise it is necessary to apply the concepts related to power consumption and power production.
By conservation of energy we know that:

Where,
Production of Power
Consumption of power
Where the production of power would be,

Where,
m = Total mass required
Energy per Kilogram
Efficiency
The problem gives us the aforementioned values under a production efficiency of 45%, that is,


Replacing the values we have,

Solving for m,


We have the mass in kilograms and the time in seconds, we need to transform this to tons per year, then,

tonnes per year.