Question

Calculate the number of moles of NaCl contained in .5000 L of a 1.5 M (Molarity) solution.

Answer 1

Answer:

The number of moles of NaCl contained in 0.5000 L of a 1.5 M (Molarity) solution is 0.75 moles.

Explanation:

Molar concentration is a measure of the concentration of a solute in a solution, be it some molecular, ionic, or atomic species.

Molarity M is the number of moles of solute that are dissolved in a given volume.

The Molarity of a solution is determined by the following expression:

$Molarity=\frac{number of moles of solute}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$.

In this case:

• Molarity= 1.5 M
• number of moles of solute= ?
• volume= 0.5 L

Reemplacing:

$1.5 M=\frac{number of moles of solute}{0.5 L}$

Solving:

number of moles of solute= 1.5 M* 0.5 L

number of moles of solute= 0.75

The number of moles of NaCl contained in 0.5000 L of a 1.5 M (Molarity) solution is 0.75 moles.