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3 years ago

How is the problem for Spots In ""One Morning Dragonville"" different from Wise Woman’s problem in this folk tale?.

Chemistry

1 answer:

Elenna [48]3 years ago

3 0

Answer:

Spots was unable to find his missing spot while the wise woman had pieces of the fallen sky with missing patches. The missing spot was part of Spot's skin and he was desperate to find it while the pieces of fallen sky did not belong to the Wise Woman and she calmly solved her problem.

Explanation:

In the fairy tale Dragonville, Spots was unable to find his missing brown spot. The spots were a part of Spot's body and it made him sad to lose a part of his body. The pieces of fallen sky were not a part of the Wise Woman's body and she easily attached bright lights to the missing patches of fallen sky bought to her by the children.

Spots seemed desperate to find a solution to his problem unlike the Wise Woman who calmly resolved the issue of the missing patches.

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Explanation:

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3 years ago

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stellarik [79]

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3 years ago

Calculate the quantity of electricity obtained from 2 moles of electrons

Vinil7 [7]

The quantity of electricity : 2 Faraday = 193000 Coulomb

<h3>Further explanation</h3>

Given

2 moles of electrons

Required

The quantity of electricity

Solution

According to Faraday, the amount of current flowing in the electrolysis cell is closely related to the amount of substance that reacts

1 Faraday is the amount of electricity that is passed in the electrolysis cell to obtain 1 mole of electrons. 1 mole of electrons is equivalent to an electric charge of 96500 Coulombs.

The conversion / relationship can be stated as follows:

1 Faraday = 1 mole of electrons = 96500 Coulombs

1 faraday = coulomb / 96500

Can be formulated

Coulomb = Q = I. t so:

$\large {\boxed {\bold {1 \: Faraday \: = \: \dfrac {i \: x \: t} {96500}}}}$

so for 2 moles electrons :

= 2 x 96500 C

= 193000 C

= 2 Faraday

6 0

3 years ago

What is the percentage yield of O2 if 12.3 g of KClO3 (molar mass 123 g) is decomposed to produce 3.2 g of O2 (molar mass 32 g)

My name is Ann [436]

Answer:

The percentage yield of O2 is 66.7%

Explanation:

Reaction for decomposition of potassium chlorate is:

2KClO₃ → 2KCl + 3O₂

The products are potassium chloride and oxygen.

Let's find out the moles of chlorate.

Mass / Molar mass = Moles

12.3 g / 123 g/mol = 0.1 mol

So ratio is 2:3, 2 moles of chlorate produce 3 mol of oxygen.

Then, 0.1 mol of chlorate may produce (0.1 .3)/ 2 = 0.15 moles

Let's convert the moles of produced oxygen, as to find out the theoretical yield.

0.15 mol . 32 g/ 1mol = 4.8 g

To calculate the percentage yield, the formula is

(Produced Yield / Theoretical yield) . 100 =

(3.2g / 4.8g) . 100 = 66.7 %

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4 years ago

10. Almost all of the atoms that you encounter have (stable/unstable) nuclei.

Montano1993 [528]

Answer:

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