Answer : The correct answer for change in freezing point = 1.69 ° C
Freezing point depression :
It is defined as depression in freezing point of solvent when volatile or non volatile solute is added .
SO when any solute is added freezing point of solution is less than freezing point of pure solvent . This depression in freezing point is directly proportional to molal concentration of solute .
It can be expressed as :
ΔTf = Freezing point of pure solvent - freezing point of solution = i* kf * m
Where : ΔTf = change in freezing point (°C)
i = Von't Hoff factor
kf =molal freezing point depression constant of solvent.
m = molality of solute (m or 
)
Given : kf = 1.86 
m = 0.907 )
Von't Hoff factor for non volatile solute is always = 1 .Since the sugar is non volatile solute , so i = 1
Plugging value in expression :
ΔTf = 1* 1.86 * 0.907 )
ΔTf = 1.69 ° C
Hence change in freezing point = 1.69 °C
Answer:
Explanation:
So we take the given quotient:
ρ=176⋅g4⋅cm×4⋅cm×4⋅cm = 176⋅g64⋅cm3 = ??g⋅cm−3.
Would the cube float or sink in water? Why
Sorry for the delay! My internet is a bit bad.
P is the third sublevel. Each sublevel (the angular momentum quantum number), has its own number:
<span>s = 1, p =3, d = 5, f = 7</span>
The number of electrons for each is:
s-2
p-6
d-10
f-14
It's easier to just memorize these numbers, but the equation for determining the sublevel number is 2n (n = the principal quantum number). The principal quantum number is based on the period the element is in.
Answer: The atomic weight of the metal would be 85.47.
Explanation:
Mass of isotope 1 of metal = 84.9118
% abundance of isotope 1 of metal = 72.15% = 
Mass of isotope 2 of metal= 86.9092
% abundance of isotope 2 of metal = 27.85% = 
Formula used for average atomic mass of an element :
![A=\sum[(84.9118)\times \frac{72.15}{100})+(86.9092)\times \frac{27.85}{100}]]](https://tex.z-dn.net/?f=A%3D%5Csum%5B%2884.9118%29%5Ctimes%20%5Cfrac%7B72.15%7D%7B100%7D%29%2B%2886.9092%29%5Ctimes%20%5Cfrac%7B27.85%7D%7B100%7D%5D%5D)
Therefore, the atomic weight of the metal would be 85.47.
A graph shows a relationship between two variables: independent and dependent. The dependent variable is in the y-axis, while the independent variable is in the x-axis. When it says, plot velocity against time, that means that
velocity is in the y-axis in meters per second, and time is in the x-axis in seconds. An example of a velocity vs time graph is shown in the attached picture. In this example, the motion is in constant acceleration. This is because it is linear, thereby, the slope is constant. If you want to find the instantaneous velocity at a certain time, create a vertical line from the x-axis until it reaches the diagonal line. Then, draw a horizontal line towards the y-axis to know the value of the velocity.
