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chubhunter [2.5K]
3 years ago
13

You are a marine biologist who wants to study what type of zooplankton (microscopic animals that live in the ocean and feed larg

er organisms) inhabit a particular area of the Pacific Ocean. You have taken your samples, but now need to collect your data. What advantage would using a compound light microscope have over using a dissecting microscope? can anyone help me
Chemistry
1 answer:
timama [110]3 years ago
4 0

Answer:

The advantage of the compound light microscope over the dissecting microscope is the magnification power of the telescope. Compound light microscope magnifies from 40x up to 1,000x while dissecting microscope magnifies up to 40 x only. In this regard, more magnification power is advantageous to view smaller objects. 

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What type of element is Hydrogen? Where do you see hydrogen present?
PSYCHO15rus [73]

/~\ The correct answer is:

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

<em><u>Hydrogen is a chemical and is </u></em><em><u>found in the sun and most of the stars, </u></em><em><u>and the</u></em><em><u> planet Jupiter</u></em><em><u> is composed mostly of hydrogen. On Earth,</u></em><em><u> </u></em><em><u>hydrogen is found in the</u></em><em><u> greatest quantities as water.</u></em>

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8 0
3 years ago
Which statement correctly describes the location and charge of the protons in an atom?
Bezzdna [24]

Answer:

Protons are located in the nucleus and have a positive charge and a mass of 1.

Explanation:

Know about protons, neutrons, and electrons.

6 0
4 years ago
Radio waves travel at the speed of light which is 3.00 x 10^8. How many minutes does it take for a radio message to reach saturn
ryzh [129]

Answer:

43.89 min

Explanation:

Given that:-

The speed of light = 3.00\times 10^8\ m/s

The distance = 7.9\times 10^8\ km

The conversion of distance in km to distance into m is shown below as:-

1 km = 1000 m

So,

Distance = 7.9\times 10^8\times 1000\ m=7.9\times 10^{11}\ m

The relation between speed distance and time is shown below as:-

Speed=\frac{Distance}{Time}

Thus,

3.00\times 10^8=\frac{7.9\times 10^{11}}{Time}

300000000\times time=10^{11}\times \:7.9\ s

Time = 2633.33 seconds

Also, 1 s = 1/60 min

So,

Time=\frac{2633.33}{60}\ min=43.89\ min

3 0
3 years ago
If a buffer solution is 0.220 M in a weak acid ( Ka=7.4×10−5) and 0.540 M in its conjugate base, what is the pH?
valkas [14]

Answer: the pH of the solution is 4.52

Explanation:

Consider the weak acid as Ha, it is dissociated as expressed below

HA     H⁺  +  A⁻

the Henderson -Haselbach equation can be expressed as;

pH = pKa + log( [A⁻] / [HA])

the weak acid is dissociated into H⁺ and A⁻ ions in the solution.

now the conjugate base of the weak acid HA is

HA(aq) {weak acid}     H⁺(aq)  +  A⁻(aq) {conjugate base}

so now we calculate the value of Kₐ as well as pH value by substituting the values of the concentrations into the equation;

pKₐ = -logKₐ

pKₐ = -log ( 7.4×10⁻⁵ )

pKₐ = 4.13

now thw pH is

pH = pKₐ  + log( [A⁻] / [HA])

pH = 4.13 + log( [0.540] / [0.220])

pH = 4.13 + 0.3899

pH = 4.5199 = 4.52

Therefore the pH of the solution is 4.52

6 0
3 years ago
2HgO(s)----&gt;2Hg(I)+O2(g) which type of reaction occurs
kaheart [24]
Decomposition,because 1 breaks down into 2
8 0
3 years ago
Read 2 more answers
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