Answer:
The specific heat capacity of silver is 0.24 j/g.°C.
Explanation:
Given data:
Mass of sample = 55.00 g
increase of temperature ΔT= 15.0 °C
Heat absorbed = 193.9 J
Specific heat capacity of silver = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance.
ΔT = change in temperature
Now we will put the values in formula.
193.9 J = 55.00 g × c ×15.0 °C
193.9 J = 825 g.°C × c
c = 193.9 J / 825 g.°C
c= 0.24 /g.°C
The specific heat capacity of silver is 0.24 j/g.°C.
1) 2C₆H₆ + 15O₂ = 6H₂O + 12CO₂
2) n(C₆H₆)/2=n(CO₂)/12
n(CO₂)=6n(C₆H₆)
n(CO₂)=6*12.8 mol = 76.8 mol
Molarmass of <span>Zn(C2H3O2)4 is 301.5561 g/mol
moles of </span>
<span>Zn(C2H3O2)4
= 62 g * 1 mol/(</span><span>301.5561 g) = 0.2056 mol
concentration = moles / volume
concentration * volume = moles
volume = moles / concentration
volume = 0.2056 mol / 1.5 M
volume = 0.13706 L
volume = 137 mL
volume = 140 mL
</span>
Answer:
The mass of reactants and products for the reaction is this:
- 92 g Na, 32 g O₂, 124 g Na₂O
which is not a choice from the list.
Explanation:
4 moles of Na reacts with 1 mol of oxygen to produce 2 moles of sodium oxide.
Na = 23 g/m
4 moles are (4 . 23) = 92 g
O₂ = 32 g/m
It's a diatomic molecule (each O is 16 g/m)
Na₂O = 62 g/m
2 mol of sodium oxide will be (2 .62) = 124 grams
The mass of reactants and products for the reaction is this:
- 92 g Na, 32 g O₂, 124 g Na₂O
which is not a choice from the list.
