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Ierofanga [76]
3 years ago
9

Please help I’ll even give you brainliet

Chemistry
1 answer:
xz_007 [3.2K]3 years ago
6 0

Answer: Na2C2O4 probably sodium oxalate

Explanation: assume you have 100 g substance.

Mass of Na is m(Na) = 34.31 g, m(C) = 17.93 g and m(O) = 47.76 g.

Calculate moles n(Na) = 34.31 g/22.99 g/mol= 1.49 mol.

For C n(C) = 1.49 mol and n(O) = 2.985. You divide all by 1.49 you

Get n(Na) : n(C) : n(O) = 1:1:2 M(NaCO2) = 67 g/mol.

Divide 134:67 = 2. You get formula Na2C2O4

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