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rewona [7]
3 years ago
15

Help asp

Chemistry
1 answer:
aalyn [17]3 years ago
7 0

Answer:

synthesis reaction

Explanation:

i need to put 20 characters. So

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<span>The answer is m = 580,5 g</span>
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In the unit 2 lab, what combination produced a brown bubbly liquid that looks like root-beer? (Select the two parts of the combi
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HELPP ME PLEASE!! What would be the density of a 40 g object that displaces 10 ml of water?
Snezhnost [94]

Answer:

<h2>The answer is 4.0 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 40 g

volume = 10 mL

The density of the object is

density =  \frac{40}{10}  = 4 \\

We have the final answer as

<h3>4.0 g/mL</h3>

Hope this helps you

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What is the value of the temp 15 degrees Celsius in degree kelvin
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3 years ago
Ka/KbMIXED PRACTICE108.Calculate the [H3O+(aq)], the pH, and the % reaction for a 0.50 mol/L HCN solution. ([H3O+(aq)] = 1.8 x 1
NeTakaya

Answer:

a) [H₃O⁺] = 1.8x10⁻⁵ M

b) pH = 4.75

c) % rxn = 3.5x10⁻³ %

Explanation:

a) The dissociation reaction of HCN is:

HCN(aq) + H₂O(l) ⇄ H₃O⁺(aq) + CN⁻(aq)

0.5 M - x                       x               x

The dissociation constant from the above reactions is given by:

Ka = \frac{[H_{3}O^{+}][CN^{-}]}{[HCN]} = 6.17 \cdot 10^{-10}

6.17 \cdot 10^{-10} = \frac{x*x}{(0.5 - x)}

6.17 \cdot 10^{-10}*(0.5 - x) - x^{2} = 0

By solving the above quadratic equation we have:

x = 1.75x10⁻⁵ M = 1.8x10⁻⁵ M = [H₃O⁺] = [CN⁻]

Hence, the [H₃O⁺] is 1.8x10⁻⁵ M.

b) The pH is equal to:

pH = -log[H_{3}O^{+}] = -log(1.75 \cdot 10^{-5} M) = 4.75    

Then, the pH of the HCN solution is 4.75.

c) The % reaction is the % ionization:

\% = \frac{x}{[HCN]} \times 100

\% = \frac{1.75 \cdot 10^{-5} M}{0.5 M} \times 100

\% = 3.5 \cdot 10^{-3} \%          

Therefore, the % reaction or % ionization is 3.5x10⁻³ %.

I hope it helps you!      

6 0
3 years ago
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