Answer:
poor hydrogen-ion donor
Explanation:
Acid dissociation constant constant chemistry is the equilibrium constant of the dissociation reaction of an acid, it is denoted by Ka. This equilibrium constant is a measure of the strength of an acid in a solution.
Note these as a rule of thumb:
When Ka is large, the dissociation of the acid is favored.
When Ka is small, the acid does not dissociate to a large extent.
Hence, a Ka of 4.3 x 10-7 shows a weak acid. A weak acid is a poor hydrogen ion donor because it does not dissociate to a large extent in solution.
Answer: C. The number of atoms of each element is the same on each side of the equation.
Explanation:
The Law of Conservation of Matter shows that it is not possible for matter to either be created nor for it to be destroyed so the number of atoms of each element on the reactant side of the equation must equal the number of atoms in each element on the product side of the equation.
This is why the following equation is incomplete:
H₂ + O₂ ⇒ H₂O
The oxygen atoms are not the same on either side.
Equation will therefor have to be balanced which will make it:
2H₂ + O₂ ⇒ 2H₂O
Notice now that atoms are the same on both sides.
Answer: The heat transfer by convection requires a solid-fluid interface, a temperature difference between the solid surface and the surrounding fluid and a motion of the fluid. The process of heat transfer by convection would occur when there is a movement of macro-particles of the fluid in space from a region of higher temperature to lower temperature.
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Answer:
The pH is 7.54
Explanation:
The Henderson - Hasselbalch equation states that for a buffer solution which consists of a weak acid and its conjugate base, the buffer pH is given by:
pH ![=pk_{a} +log(\frac{[conjugate base]}{[weakacid]})](https://tex.z-dn.net/?f=%3Dpk_%7Ba%7D%20%2Blog%28%5Cfrac%7B%5Bconjugate%20base%5D%7D%7B%5Bweakacid%5D%7D%29)
pkₐ is for the acid
In this case, the buffer hypochlorous acid HClO is a weak acid, and its conjugate base is the hypochlorite anion ClO⁻ is delivered to the solution via sodium hypochlorite NaClO
.
NaCIO = 0.200 M
HCIO = 0.200 M
pkₐ = -log₁₀ kₐ = -log₁₀ (2.9 × 10⁻⁸) = 7.54
∴pH = 
= 7.54
