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3 years ago

A light wave has a wavelength of 450 nanometers. What is the frequency of this light?

Physics

1 answer:

Zolol [24]3 years ago

3 0

Answer:

Frequency, $f=6.67\times 10^{14}\ Hz$

Explanation:

Wavelength of a light wave is 450 nm. It is required to find the frequency of this light wave. The speed of light is given by c. So,

$c=f\lambda$

f is the frequency of this light

$f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{450\times 10^{-9}}\\\\f=6.67\times 10^{14}\ Hz$

So, the frequency of this light is $6.67\times 10^{14}\ Hz$ .

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Work out the following a) Find β = v/c for a person walking at 3 mile/hr and a truck moving at 65 mile/hr. (b) Find γ-1, where γ

balu736 [363]

Explanation:

It is given that,

Speed of the person, v = 3 mile/hr = 1.34 m/s

Speed of the truck, v' = 65 mile/hr = 29.05 m/s

(a) Since, $\beta =\dfrac{v}{c}$

For the person, $\beta =\dfrac{1.34}{3\times 10^8}=4.47\times 10^{-9}$

For the truck, $\beta =\dfrac{29.05}{3\times 10^8}=9.68\times 10^{-8}$

(b) The relativistic factor is given by :

$\gamma=\dfrac{1}{\sqrt{1-\beta^2}}$

For very small velocity, $\beta$

$\gamma=(1-\beta ^2)^{-1/2}\approx 1+\dfrac{1}{2}\beta ^2$

$\gamma-1=\dfrac{\beta^2}{2}$

For the person :

$\gamma-1=\dfrac{(4.47\times 10^{-9})^2}{2}=9.99\times 10^{-18}$

For the person :

$\gamma-1=\dfrac{(9.68\times 10^{-8})^2}{2}=4.68\times 10^{-15}$

Hence, this is the required solution.

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3 years ago

If a switch is open in a series circuit with a battery trying to light a bulb, what will happen? The bulb will light up. O The s

almond37 [142]

Answer:

The bulb will not light up

If the switch is open then the connection between the circuit broken and the bulb stops glowing

The circuit needs to be closed and connected.

The circuit is the closed path through which current flows.

It consists of cell , battery , wires, resistors etc

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2 years ago

The properties of elements in compounds are usually _______ the properties of the elements alone.

KATRIN_1 [288]

are usually different from the property. only mixture takes the similar property of its constituent element

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3 years ago

Find the acceleration of a car with the mass of 1,200 kg and a force of

Mashutka [201]

Answer:9.17 m/s^2

Explanation:

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Force=11 x 10^3 N

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2 years ago