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SSSSS [86.1K]
3 years ago
12

A light wave has a wavelength of 450 nanometers. What is the frequency of this light?

Physics
1 answer:
Zolol [24]3 years ago
3 0

Answer:

Frequency, f=6.67\times 10^{14}\ Hz

Explanation:

Wavelength of a light wave is 450 nm. It is required to find the frequency of this light wave. The speed of light is given by c. So,

c=f\lambda

f is the frequency of this light

f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{450\times 10^{-9}}\\\\f=6.67\times 10^{14}\ Hz

So, the frequency of this light is 6.67\times 10^{14}\ Hz.

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An object is acted upon by a force of 22 newtons to the right and a force of 13 newtons to the left. What is the magnitude and d
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Calculate the change in length of a Pyrex glass dish (Coefficient of linear expansion for Pyrex is 3 x 10^-6 /C) that is 0.3 met
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Answer:

0.000225 m

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\frac{\Delta L}{L} = \alpha_L\Delta T\\\Rightarrow \Delta L=\alpha_L\Delta T\times L\\\Rightarrow \Delta L=3\times 10^{-6}\times 0.3\times 250=0.000225\ m

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The temperature scale which starts at absolute zero is the _____.
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Read 2 more answers
Resistor is made of a very thin metal wire that is 3.2 mm long, with a diameter of 0.4 mm. What is the electric field inside thi
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Complete question:

Resistor is made of a very thin metal wire that is 3.2 mm long, with a diameter of 0.4 mm. What is the electric field inside this metal resistor? If the potential difference due to electric field between the two ends of the resistor is 10 V.

Answer:

The electric field inside this metal resistor is 3125 V/m

Explanation:

Given;

length of the wire, L = 3.2 mm = 3.2 x 10⁻³ m

diameter of the wire, d = 0.4 mm = 0.4 x 10⁻³ m

the potential difference due to electric field between the two ends of the resistor, V = 10 V

The electric field inside this metal resistor is given by;

ΔV = EL

where;

ΔV is change in electric potential

E = ΔV / L

E = 10 / (3.2 x 10⁻³ )

E = 3125 V/m

Therefore, the electric field inside this metal resistor is 3125 V/m

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