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3 years ago

PLEASE HELP!!!!! WORTH 50 POINTS! PLEASE ANSWER ALL QUESTIONS (6,7,8,9)

Mathematics

1 answer:

iogann1982 [59]3 years ago

7 0

Answer:

6. Additional information is required on the two triangles

7. The pair of triangles are similar by SAS similarity postulate

8. Yes, by triangle proportionality theorem

9. DE = 9

Step-by-step explanation:

When two or more triangles are similar, the ratio of the corresponding sides of both triangles is constant

6. From the given figure, more information is required on the two triangles

However, whereby the side with length 10 is parallel to the corresponding side on the other triangle, then the alternate angles formed by the transversal to the two parallel lines are equal and the two triangles are similar by Angle Angle, AA, similarity postulate

7. From the given triangles, the ratio of the corresponding sides relative to the given included angles are;

18/45 and 10/25

18/45 = 2/5

10/25 = 2/5

Therefore, given that two pair of corresponding sides have the same included angle and that the two included corresponding sides of the of the two triangles are proportional, then the two triangles are similar by the Side Angle Side SAS similarity postulate

8. By triangle proportionality theorem, we have;

If $\overline{MN}$ ║ $\overline{KL}$ , then we have;

3/6 = 4/8 = 2

∴ $\overline{MN}$ ║ $\overline{KL}$

9. By triangle proportionality theorem, where $\overline{BE}$ ║ $\overline{CD}$ , we have;

12/20 = DE/15

∴ DE = 15 × 12/20 = 9

DE = 9

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A random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specime

MrRissso [65]

Answer:

We conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

We conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

Step-by-step explanation:

We are given a random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specimen;

1.10, 5.09, 0.97, 1.59, 4.60, 0.32, 0.55, 1.45, 0.14, 4.47, 1.20, 3.50, 5.02, 4.67, 5.22, 2.69, 3.98, 3.17, 3.03, 2.21, 0.69, 4.47, 3.31, 1.17, 0.76, 1.17, 1.57, 2.62, 1.66, 2.05.

Let $\mu$ = true average percentage of organic matter

So, Null Hypothesis, $H_0$ : $\mu$ = 3% {means that the true average percentage of organic matter in such soil is 3%}

Alternate Hypothesis, $H_A$ : $\mu \neq$ 3% {means that the true average percentage of organic matter in such soil is something other than 3%}

The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean percentage of organic matter = 2.481%

s = sample standard deviation = 1.616%

n = sample of soil specimens = 30

So, the test statistics = $\frac{2.481-3}{\frac{1.616}{\sqrt{30} } }$ ~ $t_2_9$

= -1.76

The value of t-test statistics is -1.76.

(a) Now, at 10% level of significance the t table gives a critical value of -1.699 and 1.699 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

(b) Now, at 5% level of significance the t table gives a critical value of -2.045 and 2.045 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

8 0

3 years ago

Please answer!!!!!!!!!!!!!!!!!

laiz [17]

The answer is B, the green is f(x)=x^2 and the red one is g(x)=f(2x).