Answer:
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Answer:
I = 8.3 Amp
potential drop = 83 V
Explanation:
Power = 100 KW
V = 12,000 V
R = 10 ohms
a)
Calculate current I in each wire:
P = I*V
I = P / V
I = 100 / 12 = 8.333 A
b)
Calculate potential drop in each wire:
V = I*R
V = (8.3) * (10)
V = 83 V
Answer:
a fluid power engine okk done please
Answer:
investor claim is acceptable
Explanation:
given data
Win = 0.25 kW
Qc = 3000 J/s = 3kW
Th = 293 K
Tc = 270 K
solution
we get here coefficient of performance of cycle is
coefficient of performance =
..................1
put here value and we get
coefficient of performance =
coefficient of performance = 1.2
and
coefficient of performance of ideal refrigeration is
coefficient of performance =
..................2
coefficient of performance =
coefficient of performance = 11.74
and
we can see here that coefficient of performance of ideal refrigeration is is more than real cycle coefficient of performance
so investor claim is acceptable