Answer: thermometer
Explanation:
Hi, a thermometer is usually a bulb or a spring thermometer. Both work by having a liquid, either alcohol and mercury, enclosed in a vacuum and the liquid expands as the temperature rises. Colored alcohol or mercury rises along a scale in a bulb thermometer whereas expanding liquid rotates a spring to turn an indicator needle around along a circular scale on a spring thermometer. Thermometers now have digital scale displays.
Answer:
a) 53 MPa, 14.87 degree
b) 60.5 MPa
Average shear = -7.5 MPa
Explanation:
Given
A = 45
B = -60
C = 30
a) stress P1 = (A+B)/2 + Sqrt ({(A-B)/2}^2 + C)
Substituting the given values, we get -
P1 = (45-60)/2 + Sqrt ({(45-(-60))/2}^2 + 30)
P1 = 53 MPa
Likewise P2 = (A+B)/2 - Sqrt ({(A-B)/2}^2 + C)
Substituting the given values, we get -
P1 = (45-60)/2 - Sqrt ({(45-(-60))/2}^2 + 30)
P1 = -68 MPa
Tan 2a = C/{(A-B)/2}
Tan 2a = 30/(45+60)/2
a = 14.87 degree
Principal stress
p1 = (45+60)/2 + (45-60)/2 cos 2a + 30 sin2a = 53 MPa
b) Shear stress in plane
Sqrt ({(45-(-60))/2}^2 + 30) = 60.5 MPa
Average = (45-(-60))/2 = -7.5 MPa
Answer:
#include <iostream>
#include <string>
using namespace std;
bool isPalindrome(string str)
{
int length = str.length();
for (int i = 0; i < length / 2; i++)
{
if (tolower(str[i]) != tolower(str[length - 1 - i]))
return false;
}
return true;
}
int main()
{
string s[6] = {"madam", "abba", "22", "67876", "444244", "trymeuemyrt"};
int i;
for(i=0; i<6; i++)
{
//Testing function
if(isPalindrome(s[i]))
{
cout << "\n " << s[i] << " is a palindrome... \n";
}
else
{
cout << "\n " << s[i] << " is not a palindrome... \n";
}
}
return 0;
}
Answer:
The flexural strength of a specimen is = 78.3 M pa
Explanation:
Given data
Height = depth = 5 mm
Width = 10 mm
Length L = 45 mm
Load = 290 N
The flexural strength of a specimen is given by
78.3 M pa
Therefore the flexural strength of a specimen is = 78.3 M pa
