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slega [8]
2 years ago
10

Why are metal containers not used for storing acids​

Chemistry
2 answers:
valentina_108 [34]2 years ago
6 0
I’m pretty sure they are, but it depends on which acids. Some acids have a really high or low ph that can burn through items, like our stomach acid. Instead, something with a high melting point would be used.
Lady_Fox [76]2 years ago
3 0
<h2>Answer:</h2>

Metal containers are not used for storing acid because most of the time acid reacts with almost every metal and produces salts or <em><u>oxides</u></em> which alters the acid characteristics making it <em>useless.</em><em>.</em><em>.</em><em>.</em>

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Sulfur oxide is a main source of acid deposition. <br> a. True <br> b. False
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3 years ago
In the laboratory, a general chemistry student measured the pH of a 0.486 M aqueous solution of triethanolamine, C6H15O3N to be
STatiana [176]

Answer:

Kb = 6.22x10⁻⁷

Explanation:

Triethanolamine, C₆H₁₅O₃N, is in equilibrium with water:

C₆H₁₅O₃N(aq) + H₂O(l) ⇄ C₆H₁₅O₃NH⁺(aq) + OH⁻(aq)

Kb is defined from concentrations in equilibrium, thus:

Kb = [C₆H₁₅O₃NH⁺] [OH⁻] / [C₆H₁₅O₃N]

The equilibrium concentration of these compounds could be written as:

[C₆H₁₅O₃N] = 0.486M - X

[C₆H₁₅O₃NH⁺] = X

[OH⁻] = X

pH is -log [H⁺], thus, [H⁺] = 10^-pH = 1.820x10⁻¹¹M

Also, Kw = [OH⁻] ₓ [H⁺];

1x10⁻¹⁴ = [OH⁻] ₓ [H⁺]

1x10⁻¹⁴ = [OH⁻] ₓ [1.820x10⁻¹¹M]

5.495x10⁻⁴M = [OH⁻], that means <em>X = 5.495x10⁻⁴M</em>

Replacing in Kb formula:

Kb = [5.495x10⁻⁴M] [5.495x10⁻⁴M] / [0.486M-5.495x10⁻⁴M]

<em>Kb = 6.22x10⁻⁷</em>

<em></em>

5 0
3 years ago
If the pressure inside your ballon is 800mmHG ,and the gas is at body temperature,37 degree Celsius , calculate the number of gr
SpyIntel [72]
With all of the information given (pressure, volume, temperature, and the molar mass), we need a formula that relates this all together. The formula we need is the ideal gas law, PV=nRT. Since the pressure is defined in millimeters of mercury, we need the R value that correlates with this, which is 62.4; on top of this, we need the temperature in Kelvin - simply add 273.15 to convert from Celsius. With all of this information, simply plug-and-chug:

PV=nRT
(800)(3.7) = n(62.4)(37 + 273.15)
n = 0.1529 moles

Finally, the problem is asking the amount of air in grams. We have moles, so all we need to do is multiply that value by the molar mass.

0.1529 moles x 29 grams per mole =
4.435 grams of air

The balloon has 4.435 grams of air inside it.

Hope this helps!
6 0
3 years ago
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