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weeeeeb [17]
3 years ago
7

BRainlist and 25 Points How do we (humans) use charoite? Give 4 ways

Chemistry
1 answer:
puteri [66]3 years ago
5 0

Answer:

Blood pressure, jewlery, design, and as a cleanser

Explanation:

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One tank of gold fish is fed the normal amount of food once a day. A second tank is fed twice a day. A third tank is fed four ti
Arturiano [62]

The question is incomplete, the complete question is;

One tank of goldfish is feed the normal amount which is once a day, a second tank is fed twice a day, and a third tank is fed four times a day during a 6 week study. The fishes' body fat is recorded daily.

Independent Variable-

Dependent Variable-

Constants

Control Group-

Answer:

A) The amount of food the gold fish receives

B) Body fat of the gold fish

C) -Type of fish used in the study (gold fish)

Time period within which the fishes were fed (Six week period)

Shape and size of tank

D) group of gold fish fed the normal amount

Explanation:

The purpose of the study is to determined the impact of amount of feed on the body fat of gold fish. Hence, the amount of feed is the independent variable while the body fat of the feed is the dependent variable.

The control group receives the normal amount of feed (once a day). The fishes are all gold fish, fed within a six week period. All the tanks were of the same shape and size. These are the constants in the study.

4 0
3 years ago
Match each group on the periodic table with its description. HELP ME PLS
Artist 52 [7]
Very reactive nonmetals.
3 0
2 years ago
When an unsymmetrical alkene such as propene is treated with N-bromosuccinimide in aqueous dimethyl sulfoxide, the major product
grin007 [14]
All done for you no worries

3 0
3 years ago
. 125g of water has an initial temperature of 25.6°C, and is heated by 50.0g of a metal
Eduardwww [97]

Answer : The specific heat of the metal is, 0.451J/g^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of metal = 50.0 g

m_2 = mass of water  = 125 g

T_f = final temperature of mixture = 29.3^oC

T_1 = initial temperature of metal = 115.0^oC

T_2 = initial temperature of water = 25.6^oC

Now put all the given values in the above formula, we get

(50.0g)\times c_1\times (29.3-115.0)^oC=-[(125g)\times 4.18J/g^oC\times (29.3-25.6)^oC]

c_1=0.451J/g^oC

Therefore, the specific heat of the metal is, 0.451J/g^oC

4 0
3 years ago
A solution with low salt concentration would most likely cause precipitation of which kinds of proteins?
cricket20 [7]

Answer:

hydrophobic proteins (larger molecules)

Explanation:

It is generally known that larger proteins require less ionic input than do smaller proteins with lesser weight.

3 0
3 years ago
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