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iren2701 [21]
2 years ago
12

Help help me please!!!!!

Physics
1 answer:
Zanzabum2 years ago
7 0

Answer:

I think that its a or b

Explanation:

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The equation Q=CV (Charge = product of Capacitance and potential difference) tells us that the maximum charge that can be stored on a capacitor is equal to the product of it's capacitance and the potential difference across it. In this case the potential difference across the capacitor will be 12.0V (assuming circuit resistance is negligable) and it has a capacitance of 18.0μf or  18.0x10^-6f, therefore charge equals (18.0x10^-6)x12=2.16x10^-4C (Coulombs).
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A pool ball hits a second pool ball with equal mass. The first pool ball comes to a complete stop, while the second pool ball ro
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A pool ball hits a second pool ball with equal mass. The first pool ball comes to a complete stop, while the second pool ball rolls away.

The second pool ball's velocity will be the same as the first pool ball's velocity was.<em> (B)</em>  

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Object A attracts object B with a gravitational force of 5 newtons from a given distance. If the distance between the two object
alukav5142 [94]

The new force of gravitational attraction is D. 20 newtons

Explanation:

The magnitude of the gravitational force between two objects is given by :

F=G\frac{m_1 m_2}{r^2}  (1)

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the distance between them

In this problem, the initial gravitational force between the two objects A and B is

F = 5 N

When the distance between them is r.

Later, the distance is reduced in half:

r' = \frac{r}{2}

Substituting into eq.(1), we see how does the  force change:

F' = G\frac{m_1 m_2}{r'^2}=G\frac{m_1 m_2}{(r/2)^2}= 4 (G\frac{m_1 m_2}{r^2})=4F

So, the force increases by 4 times. Therefore, the new force is

F'=4F=4(5 N) = 20 N

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

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