All categories

3 years ago

Help help me please!!!!!

Physics

1 answer:

Zanzabum3 years ago

7 0

Answer:

I think that its a or b

Explanation:

You might be interested in

Cutting down trees can decrease the amount of water vapor entering the air through the processes of ____?

AlexFokin [52]

✿ Transpiration is the process by which water is carried through plants from roots and release water vapor through their leaves.

✿ Cutting down trees can decrease the amount of water vapor entering the air through the processes of <u>Transpiration</u>

5 0

3 years ago

A particle is acted on by two torques about the origin: τ→1 has a magnitude of 8 N·m and is directed in the positive direction o

lyudmila [28]

To give solution to the exercise we must use the concepts of Torque, Vector magnitude and vector direction of the forces.

For the given problem we have to

$T_i = 8Nm$

$T_j = -8.9Nm$

In this way the torque acting on the particle as a function of distance and time is,

$\tau = \frac{dL}{dt} = 8\hat{i}-8.9\hat{j}$

The net torque acting on the particle is

$\tau_{net} = \sqrt{T_i^2+T_j^2}$

$\tau_{net} = \sqrt{(8)^2+(-8.9)^2}$

$\tau_{net} = 11.967Nm$

PART B) The direction of the torque is given by,

$tan\theta = \frac{y}{x}$

$\theta = tan^{-1}\frac{y}{x}$

$\theta = tan^{-1}(\frac{-8.9}{8})$

$\theta = -48.04\°$

Therefore the torque direction is 48.04° below the x axis.

5 0

4 years ago

A 200-N force acts on a 10-kg object. The acceleration of the object is

jeyben [28]

200N/10kg = 20 m/s^2

3 0

3 years ago

Automobile air bags use the decomposition of sodium azide as their sources of gas for rapid inflation, represented in the reacti

NeTakaya

Answer : The mass of $NaN_3$ required is 71.175 grams.

Explanation :

To calculate the moles of nitrogen gas, we use the equation given by ideal gas :

PV = nRT

where,

P = Pressure of nitrogen gas = 763 torr

V = Volume of the nitrogen gas = 40.0 L

n = number of moles of gas = ?

R = Gas constant = $62.364\text{ L.torr }mol^{-1}K^{-1}$

T = Temperature of helium gas = $25^oC=273+25=298K$

Putting values in above equation, we get:

$763torr\times 40.0L=n\times 62.364\text{ L.torr }mol^{-1}K^{-1}\times 298K\\\\n=1.642mol$

Now we have to calculate the moles of $NaN_3$ .

The balanced chemical reaction is:

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

From the balanced chemical reaction, we conclude that

As, 3 moles of $N_2$ produced from 2 moles $NaN_3$

So, 1.642 moles of $N_2$ produced from $\frac{2}{3}\times 1.642=1.095$ moles $NaN_3$

Now we have to calculate the mass of $NaN_3$ .

Molar mass of $NaN_3$ = 65 g/mol

$\text{Mass of }NaN_3=\text{Moles of }NaN_3\times \text{Molar mass of }NaN_3$

$\text{Mass of }NaN_3=1.095mole\times 65g/mole=71.175g$

Therefore, the mass of $NaN_3$ required is 71.175 grams.

5 0

3 years ago

How do fish breathe

jasenka [17]

Through their gills.

5 0

3 years ago