A chair is pushed forward with a force of 185 N. The gravitational force of earth on the chair is 155 N downward. The force of f
riction acting on the chair is 55 N. Draw a free-body diagram showing all forces acting on the chair. Determine the magnitude of any missing force values AND determine the net force acting on the chair.
2 answers:
The net force on the chair is 100N
<u>Explanation:</u>
The free body diagram is attached below.
According to the condition,
when a downward gravitational force of 155N of earth acts then an equal opposite upward force of same magnitude also acts on the chair.
Therefore, the normal force acting on the chair is 155N
When a chair is pushed forward on a surface, then a frictional force also acts on it in opposite direction.
The net force acting on the chair is = F - f
Where,
F is the applied force
f is the force of friction
Net force = 155N - 55N
Fnet = 100N
Therefore, net force on the chair is 100N
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Answer:
v = √2G / R
Explanation:
For this problem we use energy conservation, the energy initiated is potential and kinetic and the final energy is only potential (infinite r)
Eo = K + U = ½ m1 v² - G m1 m2 / r1
Ef = - G m1 m2 / r2
When the body is at a distance R> Re, for the furthest point (r2) let's call it Rinf
Eo = Ef
½ m1v² - G m1 / R = - G m1
/ R
v² = 2G (1 / R - 1 / Rinf)
If we do Rinf = infinity 1 / Rinf = 0
v = √2G / R
Ef = = - G m1 m2 / R
The mechanical energy is conserved
Em = -G m1 / R
Em = - G m1 / R
R = int ⇒ Em = 0
Answer:
The Pressure is 0.20 MPa.
(b) is correct option.
Explanation:
Given that,
Change in volume = 9.05%
{tex]\dfrac{\Delta V}{V_{0}}=0.0905[/tex]
We know that.
The bulk modulus for water
We need to calculate the pressure difference
Using formula bulk modulus formula
Hence, The Pressure is 0.20 MPa.