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trapecia [35]
4 years ago
13

A chair is pushed forward with a force of 185 N. The gravitational force of earth on the chair is 155 N downward. The force of f

riction acting on the chair is 55 N. Draw a free-body diagram showing all forces acting on the chair. Determine the magnitude of any missing force values AND determine the net force acting on the chair.

Physics
2 answers:
zhenek [66]4 years ago
7 0

The net force on the chair is 100N

<u>Explanation:</u>

The free body diagram is attached below.

According to the condition,

when a downward gravitational force of 155N of earth acts then an equal opposite upward force of same magnitude also acts on the chair.

Therefore, the normal force acting on the chair is 155N

When a chair is pushed forward on a surface, then a frictional force also acts on it in opposite direction.

The net force acting on the chair is = F - f

Where,

F is the applied force

f is the force of friction

Net force = 155N - 55N

Fnet = 100N

Therefore, net force on the chair is 100N

andreyandreev [35.5K]4 years ago
5 0

Answer:

100 N

Explanation:

Me big brain

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Answer is 183.6 J

Explanation:

Using the Physics reference sheet the formula for Potential energy is

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Mass= 1.2

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How was Mendeleev first periodic table like the periodic table today
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He began organizing the known elements according to their atomic weights and chemical properties.

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A copper telephone wire has essentially
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Answer:

128.21 m

Explanation:

The following data were obtained from the question:

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Final temperature (θ₂) = 43 °C

Change in length (ΔL) = 8.5 cm

Coefficient of linear expansion (α) = 17×10¯⁶ K¯¹)

Original length (L₁) =.?

The original length can be obtained as follow:

α = ΔL / L₁(θ₂ – θ₁)

17×10¯⁶ = 8.5 / L₁(43 – 4)

17×10¯⁶ = 8.5 / L₁(39)

17×10¯⁶ = 8.5 / 39L₁

Cross multiply

17×10¯⁶ × 39L₁ = 8.5

6.63×10¯⁴ L₁ = 8.5

Divide both side by 6.63×10¯⁴

L₁ = 8.5 / 6.63×10¯⁴

L₁ = 12820.51 cm

Finally, we shall convert 12820.51 cm to metre (m). This can be obtained as follow:

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12820.51 cm = 12820.51 cm × 1 m / 100 cm

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5 0
3 years ago
It is easier to lift the same load by using three pulley system than by using two-pulley system. why give reason.​
tresset_1 [31]
<h2>QUESTION:- It is easier to lift the same load by using three pulley system than by using two-pulley system.</h2>

<h2>ANSWER:- IN CASE OF IDEAL PULLEY SYSTEM</h2>

<h2>REASON:- </h2>

Logic behind is lies behind the mechanical advantage of the provided bt the Pulley system.

as if we calculate the mechanical advantage of the 2 Pulley system we will have the value 2

And if we will calculate the mechanical advantage of the 3 pulley system then we will get the value of 3

so due to extra mechanical advantage we feel it easy to move with 3 pulley system then 2 Pulley system

\red \star{Thanks \:  And  \: Brainlist}  \blue\star \\  \green\star  If \:  U  \: Liked \:  My  \: Answer \purple \star

7 0
3 years ago
The current in a wire varies with time according to the relationship 1=55A−(0.65A/s2)t2. (a) How many coulombs of charge pass a
mario62 [17]

Answer:

(A) Q = 321.1C (B) I = 42.8A

Explanation:

(a)Given I = 55A−(0.65A/s2)t²

I = dQ/dt

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To get an expression for Q we integrate with respect to t.

So Q = ∫I×dt =∫[55−(0.65)t²]dt

Q = [55t – 0.65/3×t³]

Q between t=0 and t= 7.5s

Q = [55×(7.5 – 0) – 0.65/3(7.5³– 0³)]

Q = 321.1C

(b) For a constant current I in the same time interval

I = Q/t = 321.1/7.5 = 42.8A.

3 0
3 years ago
Read 2 more answers
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