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Westkost [7]
3 years ago
5

When the switch is open, the model predicts that bulb ___ will have the same brightness as bulb ___. When the switch is closed,

the model predicts that bulb ___ will be brighter than either bulb ___or bulb C. Both bulbs ___ and ___ will have the same brightness when the switch is closed.
Physics
1 answer:
Arte-miy333 [17]3 years ago
6 0

please show me the question paper .( Pic)

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A student measures the volume of a gas sample at several different temperatures. The results are tabulated as follows:Temperatur
lapo4ka [179]

Answer:

Check the first and the third choices:

<u><em /></u>

  • <u><em>a. The temperature of a gas is directly proportional to its volume</em></u>
  • <u><em>b. The temperature-to-volume ratio of a gas is constant.</em></u>

Explanation:

Rewrite the table for better understanding:

Temperature of gas (K)     Volume of gas (L)

     298                                     4.55

     315                                      4.81

     325                                     4.96

     335                                        ?

Calculate the ratios temperature to volume with 3 significant figures:

  • 298 / 4.55 = 65.5
  • 315 / 4.81 = 65.5
  • 325 / 4.96 = 65.5

Then, those numbers show a <u><em>constant temperature-to-volume ratio</em></u>, which may be expressed in a formula as:

  • Temperature / Volume = constant, which is a directly proportional variation (the volume increases in a constant proportion to the increase of the temperature).

Hence, the correct choices are:

  • The temperature of a gas is directly proportional to its volume (first statement), and
  • The emperature-to-volume ratio of a gas is constant (third statement).
5 0
3 years ago
What type of image results when the object is located between 2f (2 focal lengths) and f (the focal point) of a convex lens?
VikaD [51]

Answer:

C

Explanation:

the image formed is real but inverted and magnified

you can remember it by R I M

hope this helps

4 0
3 years ago
Is a cinder cone volcanoe constructive or deconstructive
Ksivusya [100]
Cinder cone volcanoes can be associated with either constructive or destructive margins.<span>
</span>
6 0
3 years ago
Explain how a book can have energy even if it is not moving.
frutty [35]
Can something have energy even if it's not moving?
All moving objects have kinetic energy. When an object is in motion, it changes its position by moving in a direction: up, down, forward, or backward. ... Potential energy is stored energy. Even when an object is sitting still, it has energy stored inside that can be turned into kinetic energy (motion).


Does a book at rest have energy?
A World Civilization book at rest on the top shelf of a locker possesses mechanical energy due to its vertical position above the ground (gravitational potential energy).



Does a book lying on a table have energy?
The book lying on a desk has potential energy; the book falling off a desk has kinetic energy.
5 0
2 years ago
A swimming pool is 50 ft wide and 100 ft long and its bottom is an inclined plane, the shallow end having a depth of 4 ft and th
Nina [5.8K]

Explanation:

We define force as the product of mass and acceleration.

F = ma

It means that the object has zero net force when it is in rest state or it when it has no acceleration. However in the case of liquids. just like the above mentioned case, the water is at rest but it is still exerting a pressure on the walls of the swimming pool. That pressure exerted by the liquids in their rest state is known as hydro static force.

Given Data:

Width of the pool = w = 50 ft

length of the pool = l= 100 ft

Depth of the shallow end = h(s) = 4 ft

Depth of the deep end = h(d) = 10 ft.

weight density = ρg = 62.5 lb/ft

Solution:

a) Force on a shallow end:

F = \frac{pgwh}{2} (2x_{1}+h)

F = \frac{(62.5)(50)(4)}{2}(2(0)+4)

F = 25000 lb

b) Force on deep end:

F = \frac{pgwh}{2} (2x_{1}+h)

F = \frac{(62.5)(50)(10)}{2} (2(0)+10)

F = 187500 lb

c) Force on one of the sides:

As it is mentioned in the question that the bottom of the swimming pool is an inclined plane so sum of the forces on the rectangular part and triangular part will give us the force on one of the sides of the pool.

1) Force on the Rectangular part:

F = \frac{pg(l.h)}{2}(2(x_{1} )+ h)

x_{1} = 0\\h_{s} = 4ft

F = \frac{(62.5)(100)(2)}{2}(2(0)+4)

F =25000lb

2) Force on the triangular part:

F = \frac{pg(l.h)}{6} (3x_{1} +2h)

here

h = h(d) - h(s)

h = 10-4

h = 6ft

x_{1} = 4ft\\

F = \frac{62.5 (100)(6)}{6} (3(4)+2(6))

F = 150000 lb

now add both of these forces,

F = 25000lb + 150000lb

F = 175000lb

d) Force on the bottom:

F = \frac{pgw\sqrt{l^{2} + ((h_{d}) - h(s)) } (h_{d}+h_{s})   }{2}

F = \frac{62.5(50)\sqrt{100^{2}(10-4) } (10+4) }{2}

F = 2187937.5 lb

7 0
3 years ago
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