<u>Answer:</u> The maximum amount of N-acetyl-p-toluidine that can be prepared is 1.7 grams.
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
Molarity of p-toluidine hydrochloride solution = 0.167 M
Volume of solution = 70. mL
Putting values in above equation, we get:
The chemical equation for the reaction of p-toluidine hydrochloride and acetic anhydride follows:
By Stoichiometry of the reaction:
1 mole of p-toluidine hydrochloride produces 1 mole of N-acetyl-p-toluidine
So, 0.0117 moles of p-toluidine hydrochloride will produce = of N-acetyl-p-toluidine
To calculate the number of moles, we use the equation:
Molar mass of N-acetyl-p-toluidine = 149.2 g/mol
Moles of N-acetyl-p-toluidine = 0.0117 moles
Putting values in equation 1, we get:
Hence, the maximum amount of N-acetyl-p-toluidine that can be prepared is 1.7 grams.