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3 years ago

What atomic or hybrid orbital on sb makes up the sigma bond between sb and f in antimony(iii) fluoride, sbf3?

Chemistry

1 answer:

Afina-wow [57]3 years ago

6 0

Answer: The four $sp^3$ hybridized orbitals on Sb makes up the sigma bonds between Sb and F in antimony(iii) fluoride , $SbF_3$

Explanation:

According to VESPR theory:

Number of electrons around the central atom : $\frac{1}{2}[V+N-C+A]$

V = number of valence electrons

N = number of neighboring atoms

C = charge on cation

A = charge on an anion

In antimony(III) fluoride ,

Antimony being central atom: V= 5,N =3,C=0,A=0

Number of electrons : $\frac{1}{2}[V+N-C+A]=4$

Number of electrons around the central atom are 4 which means that $SbF_3$ molecule has four $sp^3$ hybridized orbitals.

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Balance each of the following examples of heterogeneous equilibria and write each Kc expression. Then calculate the value of Kc

marysya [2.9K]

Explanation:

1) $2 Al(s) + 2 NaOH(aq) + 6 H_2O(l) \longleftrightarrow 2 Na[Al(OH)_4](aq) + 7 H_2(g)$

$Kc=\frac{[Na[Al(OH)_4]]^2*[H_2]^7}{[NaOH]^2}$

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

$Kc_{reverse}=\frac{1}{Kc}=\frac{1}{11}=0.091$

2) $H_2O(l) + SO_3(g) \longleftrightarrow H_2SO_4 (aq)$

$Kc=\frac{[H_2SO_4]}{[SO_3]^2}$

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

$Kc_{reverse}=\frac{1}{Kc}=\frac{1}{0.0123}=81.3$

3) $P_4(s) + 3 O_2(g) \longleftrightarrow P_4O_6(s)$

$Kc=\frac{1}{[O_2]^3}$

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

$Kc_{reverse}=\frac{1}{Kc}=\frac{1}{1.56}=0.641$

5 0

3 years ago

Calculate the pressure of 2.50 Liters of a gas at 25.0oC if it has a volume of 4.50 Liters at

MariettaO [177]

Answer:

P_2 =0.51 atm

Explanation:

Given that:

Volume (V1) = 2.50 L

Temperature (T1) = 298 K

Volume (V2) = 4.50 L

at standard temperature and pressure;

Pressure (P1) = 1 atm

Temperature (T2) = 273 K

Pressure P2 = ??

Using combined gas law:

$\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2} \\ \\ \dfrac{1 *2.5}{298} = \dfrac{P_2*4.5}{273}$

$0.008389261745 \times 273 = 4.5P_2$

$P_2 =\dfrac{0.008389261745 \times 273 }{4.5}$

$P_2 =0.51 \ atm$

4 0

3 years ago

Match each description below with the name of the local wind system being described. warm, dry downslope wind affecting Southern

nadya68 [22]

Answer:

warm, dry downslope wind affecting Southern California - Santa Ana wind

a seasonally changing wind- monsoon

wind blowing from a valley up a mountain slope - valley breeze

generated by cold thunderstorm downdrafts - haboob

Explanation:

The Santa Ana wind occurs in early autumn. They bring hot and dry weather to areas around the South-West coast. They move at high speeds, affecting most parts of Southern California.

Monsoon is a seasonal wind that blows across Southern Asia. It usually blows in summer. It is a a seasonally changing wind.

Valley breeze is an example of convection current in nature. It is produced by rapid warming of the valley floor leading to the expansion of air making it to flow up the slopes. At night, radiation from the surface cools the slopes. This leads to the rise of cooler and denser air which drains into the valley.

Haboob is generated by cold thunderstorm downdrafts. It is associated with large sandstorms and dust storms.

8 0

3 years ago

A 254.5 g sample of a white solid is known to be a mixture of KNO3, BaCl2, and NaCl. When 116.5 g of this mixture is dissolved i

Margaret [11]

Answer:

Mass of KNO3 in the original mix is 146.954 g

Explanation:

mass of $KNO_3$ in original 254.5 mixture.

moles of $BaSO_4 = \frac{mass}{Molecular\ Weight}$

moles of $BaSO_4 = \frac{68.3}{233.38}$

= 0.2926 mol of BaSO4

Therefore,

0.2926 mol of BaCl2,

mass of $BaCl_2 = mol\times molecular weight$

$= 0.2926\times 208.23$

= 60.92 g

the AgCl moles $= \frac{mass}{Molecular\ Weight}$

$= \frac{199.1}{143.32}$

= 1.3891 mol of AgCl

note that, the Cl- derive from both, $BACl_2 and NaCl$

mole of Cl- f NaCl $= (1.3891) - (0.2926\times 2) = 0.8039$ mol of Cl-

mol of NaCl = 0.8039 moles

$mass = mol\times Molecular\ Weight = 0.8039 \times 58 = 46.626\ g \ of \ NaCl$

then

KNO3 mass = 254.5 - 60.92-46.626 = 146.954 g of KNO_3

Mass of KNO3 in the original mix is 146.954 g

8 0

3 years ago

Mrs. Jacobson is pushing a fridge to the right with a force of 100 N. The force pushing it

alex41 [277]

Answer:

Explanation:

Let's illustrate this; see the attachment.

We see that Mrs. Jacobson is pushing to the right with a force of 100 N and there is another opposite force pushing with a force of 15 N. Since these are in opposite directions, we can say that the force opposite to Mrs. Jacobson is pushing the fridge -15 N to the right (instead of 15 N to the left).

The net force would then be:

100 N + (-15 N) = 85 N to the right

The answer is A.

8 0

4 years ago

Read 2 more answers