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Marta_Voda [28]
3 years ago
10

What atomic or hybrid orbital on sb makes up the sigma bond between sb and f in antimony(iii) fluoride, sbf3?

Chemistry
1 answer:
Afina-wow [57]3 years ago
6 0

Answer: The four sp^3 hybridized orbitals on Sb makes up the sigma bonds between Sb and F in antimony(iii) fluoride ,SbF_3

Explanation:

According to VESPR theory:

Number of electrons around the central atom : \frac{1}{2}[V+N-C+A]

V = number of valence electrons

N = number of neighboring atoms

C = charge on cation

A = charge on an anion

In antimony(III) fluoride ,

Antimony being central atom: V= 5,N =3,C=0,A=0

Number of electrons : \frac{1}{2}[V+N-C+A]=4

Number of electrons around the central atom are 4 which means that SbF_3 molecule has four sp^3 hybridized orbitals.

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Determine the concentration of hydronium and hydroxide ions in a solution that has a pH of 1.6.
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Answer:

The answer to your question is [H₃O⁺] = 0.025   [OH⁻] = 3.98 x 10⁻¹³

Explanation:

Data

[H⁺] = ?

[OH⁻] = ?

pH = 1.6

Process

Use the pH formula to calculate the [H₃O⁺], then calculate the pOH and with this value, calculate the [OH⁻].

pH formula

pH = -log[H₃O⁺]

-Substitution

1.6 = -log[H₃O⁺]

-Simplification

[H₃O⁺] = antilog (-1,6)

-Result

[H₃O⁺] = 0.025

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pOH = 14 - pH

-Substitution

pOH = 14 - 1.6

-Result

pOH = 12.4

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-Result

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