Answer: The four
hybridized orbitals on Sb makes up the sigma bonds between Sb and F in antimony(iii) fluoride ,
Explanation:
According to VESPR theory:
Number of electrons around the central atom : ![\frac{1}{2}[V+N-C+A]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5BV%2BN-C%2BA%5D)
V = number of valence electrons
N = number of neighboring atoms
C = charge on cation
A = charge on an anion
In antimony(III) fluoride ,
Antimony being central atom: V= 5,N =3,C=0,A=0
Number of electrons : ![\frac{1}{2}[V+N-C+A]=4](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5BV%2BN-C%2BA%5D%3D4)
Number of electrons around the central atom are 4 which means that
molecule has four
hybridized orbitals.