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3 years ago

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which one of the following is an endothermic process?1.ice melting 2.water freezing 3.a boiling soup 4.the reaction of HCl and N

AOH,temperature increases

1 answer:

Llana [10]3 years ago

8 0

<span>From the above given choices :
melting is an endothermic process</span>

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False I’m not sure exactly

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2 years ago

How to solve 5gNaCl= MolE NaCl

valentinak56 [21]

0.086mole

Explanation:

The problem is very simple. It involves conversion from mass to number of moles of NaCl

What is mole?

A mole is a unit of measuring chemical substances. It is the amount that contains the avogadro's number of particles.

How is it related and can be converted from mass;

Number of moles of a substance = $\frac{mass}{molar mass}$

Since we know the mass, we can find the molar mass and put into this equation;

Molar mass of NaCl = 23 + 35.5 = 58.5g/mol

Number of moles of NaCl = $\frac{5}{58.5} =$ 0.086mole

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3 years ago

Difference between element and radical

Romashka-Z-Leto [24]

Answer:

A radical is a group of atoms behaving as a unit in a number of compounds where as an element is a species of atoms having the same number of protons in their atomic nuclei.

Explanation:

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3 years ago

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Why is ocean water more dense than freshwater

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3 years ago

2N2H4+ N2O4———3N2+4H2O SalmaKhan99 avatar How many grams of N2 gas will be formed by reacting 100g of N2H4 and 200g of N2 Kindly

Alona [7]

Answer:

131.26 g

Explanation:

From the balanced equation,

2 moles of N₂H₄reacts with 1 mole of N₂O₄ to give 3 moles of N₂

Now number of moles of N₂H₄ present in 100 g N₂H₄ is n = 100 g/molar mass N₂H₄.

Molar mass N₂H₄ = 2 × 14.01 g/mol + 1 × 4 g/mol = 28.02 g/mol + 4 g/mol = 32.02 g/mol

n₁ = 100/32.02 = 3.123 mol

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Now number of moles of N₂O₄ present in 200 g N₂O₄ is n = 200 g/molar mass N₂O₄.

Molar mass N₂O₄ = 2 × 14.01 g/mol + 16 × 4 g/mol = 28.02 g/mol + 64 g/mol = 92.02 g/mol

n₂ = 200/92.02 = 2.173 mol

Since the mole ratio of N₂H₄ to N₂O₄ is 2 : 1, We require 2 × 2.173 mol N₂H₄ to react with 2.173 mole N₂O₄

Number of moles of N₂H₄ required is 4.346. But the number of moles of N₂H₄ present is 3.123 so N₂H₄ is the limiting reagent.

So, from the equation, 2 moles of N₂H₄ produces 3 moles of N₂

Therefore number of mole N₂ = 3/2 moles of N₂H₄ = 3/2 × 3.123 mol = 4.6845 mol

From n = m/M where n = number of moles of nitrogen gas = 4.6845 mol and M = molar mass of nitrogen gas = 28.02 g/mol and m = mass of nitogen gas.

m = nM = 4.6845 mol × 28.02 g/mol = 131.26 g

So the mas of nitrogen gas produced is 131.26 g

4 0

3 years ago