Your weight on the moon given the data from the question is 110.5 N
<h3>Definition of mass and weight </h3>
Mass is simply defined as the quantity of matter present in an object. The mass of an object is constant irrespective of the location of the object.
Weight is simply defined as the gravitational pull on an object. The weight of an object varies from place to place due to gravity.
<h3>Relationship between mass and weight </h3>
Mass and weight are related according to the following equation
Weight (W) = mass (m) × Acceleration due to gravity (g)
<h3>How to determine the weight on the moon</h3>
- Mass (m) = 65 Kg
- Acceleration due to gravity on the moon (g) = 1.7 m/s²
- Weight (W) =?
W = mg
W = 65 × 1.7
W = 110.5 N
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Answer: a switch can do A, B and E
Explanation:
Answer:
6.23x10^6Pa
Explanation:
Data obtained from the question include:
F (force) = 490N
r (radius) = 0.005m
A (area of the circlular heel) =?
P (pressure) =.?
First, we'll begin by calculating the area of the circlular heel. This is illustrated below:
Area of circle = πr^2
Area = 22/7 x (0.00)^2
Area = 7.86x10^-5m^2
Pressure is simply force per unit area. It represented mathematically as
Pressure = Force /Area
Pressure = 490/7.86x10^-5
Pressure = 6.23x10^6N/m2
Recall: 1N/m2 = 1Pa
Therefore, 6.23x10^6N/m2 = 6.23x10^6Pa
Therefore, the woman exert a pressure of 6.23x10^6Pa on the floor
Answer: it becomes a positive ion
Explanation:
So, when an atom loses 2 electrons there will be no change in the number of neutrons. Therefore, an isotope will not form. Thus, it is concluded that when an atom with no charge loses two electrons, it becomes a positive ion.
Answer:
The force is the same
Explanation:
The force per meter exerted between two wires carrying a current is given by the formula
where
is the vacuum permeability
is the current in the 1st wire
is the current in the 2nd wire
r is the separation between the wires
In this problem
Substituting, we find the force per unit length on the two wires:
However, the formula is the same for the two wires: this means that the force per meter exerted on the two wires is the same.
The same conclusion comes out from Newton's third law of motion, which states that when an object A exerts a force on an object B, then object B exerts an equal and opposite force on object A (action-reaction). If we apply the law to this situation, we see that the force exerted by wire 1 on wire 2 is the same as the force exerted by wire 2 on wire 1 (however the direction is opposite).
