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jeka94
3 years ago
14

A sample of hydrogen (H2) gas is collected over water at 35oC and 725 mm. The volume of the gas collected is 72.0 ml. How many m

oles of H2 gas has been collected? How many grams of H2 gas has been collected?
Chemistry
1 answer:
WARRIOR [948]3 years ago
3 0

Answer:

2.56 × 10⁻³ mol

5.17 × 10⁻³ g

Explanation:

Given data

Temperature = 35°C + 273 = 308 K

Pressure = 725 mmHg

Volume = 72.0 mL = 0.0720 L

The vapor pressure of water at 35°C is 42.20 mmHg. The total pressure is equal to the sum of the partial pressures.

P = pH₂ + pH₂O

pH₂ = P - pH₂O = 725 mmHg - 42.20 mmHg = 683 mmHg

pH₂ = 683 mmHg × (1 atm / 760 mmHg) = 0.899 atm

We can find the moles of H₂ using the ideal gas equation.

P × V = n × R × T

0.899 atm × 0.0720 L = n × (0.08206 atm.L/mol.K) × 308 K

n = 2.56 × 10⁻³ mol

The molar mass of H₂ is 2.02 g/mol. The mass of H₂ is:

2.56 × 10⁻³ mol × 2.02 g/mol = 5.17 × 10⁻³ g

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3 years ago
Using the Lewis dot structures of magnesium and oxygen, predict the ionic formula
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7 0
3 years ago
Give all possible ml values for orbitals that have each of the following:<br> (a) l = 3;
Angelina_Jolie [31]

At l = 3, ml =+3,+2,+1,0,-1,-2,-3

What are quantum numbers?

  • Quantum numbers are used to describe where around a nucleus a particular electron can be found.
  • In any given atom, each electron can be described by four quantum numbers.
  • These are n,l,m1,ms
  • The values that each number can be are based on a set of rules.

What is a magnetic quantum number ?

  • It describes the orientation of the orbitals.
  • It is represented as ml.
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8 0
2 years ago
The enzyme, carbonic anhydrase, is a large zinc-containing protein with a molar mass of 3.00 x10^4 g/mol. Zn is 0.218% by mass o
tia_tia [17]

The mathematical expression for mass percent is given by:

Mass percent = \frac{mass of the compound}{molar mass of the compound}\times 100

Put the values,

0.218 percent of zinc = \frac{mass of zinc}{3.00 \times 10^{4} g/mol}\times 100

mass of zinc = 0.218 \times (3\times 100) g

= 0.654 \times 100 g or 65.4 g

Now, number of moles of zinc  =\frac{given mass in g}{molar mass of zinc}

= \frac{65.4 g}{65.38 g/mol}

= 1.00 mole

Number of atoms of zinc is calculated by the Avogadro number.

Now, according to mole concept

6.022\times 10^{23} molecules of enzyme consists of 6.022\times 10^{23} atoms of zinc

So, 1 molecule of enzyme contains  =\frac{6.022\times 10^{23}atoms of zinc}{6.022\times 10^{23} }

= 1 atom of zinc.

Hence, every carbonic anhydrase molecule consists of 1 atom of zinc.



5 0
3 years ago
in a simulation mercury removal from industrial wastewater, 0.020 L of 0.10 M sodium sulfide reacts with 0.050 L of 0.010 M merc
Margarita [4]

Answer:  0.1161 grams of mercury(II) sulfide) form.

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}     .....(1)

a) Molarity of Na_2S solution = 0.10 M

Volume of solution = 0.020 L

Putting values in equation 1, we get:

0.10M=\frac{\text{Moles of }Na_2S}{0.020L}\\\\\text{Moles of Na_2S}={0.10mol/L\times 0.020}=0.002mol

\text {Moles of}Na_2S=0.10M\times 0.020L=0.002mol

b) Molarity of Hg(NO_3)_2 solution = 0.010 M

Volume of solution = 0.050 L

Putting values in equation 1, we get:

0.010M=\frac{\text{Moles of }Hg(NO_3)_2}{0.050L}\\\\\text{Moles of }Hg(NO_3)_2={0.010mol/L\times 0.050}=0.0005mol

Na_2S+Hg(NO_3)_2\rightarrow HgS+2NaNO_3

According to stoichiometry :

1 mole of Hg(NO_3)_2 reacts with 1 mole of Na_2S

Thus 0.0005 moles of HgNO_3 reacts with=\frac{1}{1}\times 0.0005=0.0005 moles of Hg(NO_3)_2

Thus Hg(NO_3)_2 is the limiting reagent and Na_2S is the excess reagent.

According to stoichiometry :

1 mole of Hg(NO_3)_2 forms=  1 mole of Hg_2S

Thus 0.0005 moles of Hg(NO_3)_2 forms=\frac{1}{1}\times 0.0005=0.0005 moles of Hg_2S

mass of H_2S=moles\times {\text {Molar mass}}=0.0005mol\times 232.2g/mol=0.1161g

Thus 0.1161 grams of mercury(II) sulfide) form.

5 0
3 years ago
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