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andrezito [222]
2 years ago
9

In the following chemical reaction, which compound is a precipitate? NaCl(aq) + AgNO3(aq)NaNO3(aq) + AgCI (s)

Chemistry
2 answers:
disa [49]2 years ago
8 0

Answer: D: AgCl is the correct answer

hjlf2 years ago
4 0
The answer is:  [D]:  " AgCl " .
_________________________________________________________ 

Explanation:

_________________________________________________________

Given the chemical reaction:
_________________________________________________________
  
       NaCl (aq) + AgNO₃ (aq) <span>→ </span> NaNO₃ (aq) + AgCl (s)   ;
_________________________________________________________

The "reactants" , which are on the "left-hand side" of the chemical equation, are:

"NaCl" (in aqueous solution);  and "AgNO₃" (in aqueous solution).

The "products", which are on the "right-hand side" of the chemical equation, are: 

"NaNO₃" (in aqueous solution); and:  "AgCl" (as a "solid").

The "AgCl" (as a "product"—which is a "solid"—would be the "precipitate" ; 
__________________________________________________________

   →  which is:  Answer choice:  [D]:  " AgCl " . 
__________________________________________________________
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(C6H6) can be biodegraded by microorganism. if 30 mg of benzene is present, what amount of oxygen required for biodegradation, n
quester [9]

Answer:

36.92 mg of oxygen required for bio-degradation.

Explanation:

5C_6H_6+15O_2\rightarrow 12CO_2+15H_2O

Mass of benzene = 30 mg = 0.03 g (1000 mg = 1 g )

Moles benzene =\frac{0.03 g}{78 g/mol}=0.0003846 mol

According to reaction 5 moles of benzene reacts with 15 moles of oxygen gas.

Then 0.0003846 mol of benzene will react with:

\frac{15}{5}\times 0.0003846 mol=0.0011538 mol of oxygen gas

Mass of 0.0011538 moles of oxygen gas:

0.0011538 mol × 32 g/mol = 0.03692 g = 36.92 mg

36.92 mg of oxygen required for bio-degradation.

4 0
2 years ago
Using the following thermochemical data, what is the change in enthalpy for the following reaction? Ca(OH)2(aq) + HCl(aq) CaCl2(
sesenic [268]
Ca(OH)2(aq) + 2HCl(aq)------> CaCl2(aq) + 2H2O(l) ΔH-?

CaO(s) + 2HCl(aq)-----> CaCl2(aq) + H2O(l),  Δ<span>H = -186 kJ
</span>
CaO(s) + H2O(l) -----> Ca(OH)2(s), Δ<span>H = -65.1 kJ
</span>
1) Ca(OH)2 should be  reactant, so
CaO(s) + H2O(l) -----> Ca(OH)2(s) 
we are going to take as 
 Ca(OH)2(s)---->CaO(s) + H2O(l), and ΔH = 65.1 kJ

2) Add 2 following equations
Ca(OH)2(s)---->CaO(s) + H2O(l),                    and ΔH = 65.1 kJ
<span><u>CaO(s) + 2HCl(aq)-----> CaCl2(aq) + H2O(l), and ΔH = -186 kJ</u>

</span>Ca(OH)2(s)+CaO(s) + 2HCl(aq)--->CaO(s) + H2O(l)+CaCl2(aq) + H2O(l)

Ca(OH)2(s)+ 2HCl(aq)---> H2O(l)+CaCl2(aq) + H2O(l)
By addig these 2 equation, we got the equation that we are needed,
so to find enthalpy of the reaction, we need to add  enthalpies of reactions we added.
ΔH=65.1 - 186 ≈ -121 kJ
4 0
3 years ago
Empirical formula of a compound composed of 32.1 g potassium (k) and 6.57 g oxygen (o)?
tester [92]

The empirical formula is K₂O.

The empirical formula is the <em>simplest whole-number ratio</em> of atoms in a compound.

The <em>ratio of atom</em>s is the same as the <em>ratio of moles</em>.

So, our job is to calculate the <em>molar ratio</em> of K to O.

Step 1. Calculate the <em>moles of each element </em>

Moles of K = 32.1 g K × (1 mol K/(39.10 g K =) = 0.8210 mol K

Moles of O = 6.57 g O × (1 mol O/16.00 g O) = 0.4106 mol 0

Step 2. Calculate the <em>molar ratio of each elemen</em>t

Divide each number by the smallest number of moles and round off to an integer

K:O = 0.8210:0.4106 = 1.999:1 ≈ 2:1

Step 3: Write the <em>empirical formula </em>

EF = K₂O

5 0
2 years ago
Which of the following is not included in John Dalton's modern theory of the atom?
Akimi4 [234]

The answer for the following question is option "C".

Option C is not included in the John Dalton's modern theory of an atom.

  • "It states atoms of different elements combine to form new compound" but not new elements

Explanation:

According to John's Dalton's modern theory of an atom:

1. All matter is composed of atoms.

2. Atoms cannot be created,destroyed or subdivided in the ordinary chemical reactions.

3. Atoms of one element differ in the properties from atoms of an another element.

(i.e.)Each and every atom of the element has its own unique properties of their own.

4. Atoms of one  element combine with the atoms of another element to <u>form new compound.</u>

5. Atoms that make up an element are identical to each other.

7 0
3 years ago
What type(s) of intermolecular forces are expected between ch3ch2ch2ch2ch2oh molecules?
notka56 [123]

Answer : Hydrogen-bonding, Dipole-dipole attraction and London-dispersion force.

Explanation :

The given molecule is, CH_3CH_2CH_2CH_2CH_2OH

Three types of inter-molecular forces are present in this molecule which are Hydrogen-bonding, Dipole-dipole attraction and London-dispersion force.

  • Hydrogen-bonding : when the partial positive end of hydrogen is bonded with the partial negative end of another molecule like, oxygen, nitrogen, etc.
  • Dipole-dipole attraction : When the partial positively charged part of the molecule is interact with the partial negatively charged part of the molecule. For example : In case of HCl.
  • London-dispersion force : This force is present in all type of molecule whether it is a polar or non-polar, ionic or covalent. For example : In case of Br-Br , F-F, etc

Hydrogen-bonding is present between the oxygen and hydrogen molecule.

Dipole-dipole forces is present between the carbon and oxygen molecule.

London-dispersion forces is present between the carbon and carbon molecule.

5 0
3 years ago
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