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andrezito [222]
3 years ago
9

In the following chemical reaction, which compound is a precipitate? NaCl(aq) + AgNO3(aq)NaNO3(aq) + AgCI (s)

Chemistry
2 answers:
disa [49]3 years ago
8 0

Answer: D: AgCl is the correct answer

hjlf3 years ago
4 0
The answer is:  [D]:  " AgCl " .
_________________________________________________________ 

Explanation:

_________________________________________________________

Given the chemical reaction:
_________________________________________________________
  
       NaCl (aq) + AgNO₃ (aq) <span>→ </span> NaNO₃ (aq) + AgCl (s)   ;
_________________________________________________________

The "reactants" , which are on the "left-hand side" of the chemical equation, are:

"NaCl" (in aqueous solution);  and "AgNO₃" (in aqueous solution).

The "products", which are on the "right-hand side" of the chemical equation, are: 

"NaNO₃" (in aqueous solution); and:  "AgCl" (as a "solid").

The "AgCl" (as a "product"—which is a "solid"—would be the "precipitate" ; 
__________________________________________________________

   →  which is:  Answer choice:  [D]:  " AgCl " . 
__________________________________________________________
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Read 2 more answers
a sample of 3.00 g of so2 (g)originally in a 5.00 L vesselat 21 degee Celsius is transferred to a 10.0 L vessel at 26 degree Cel
eimsori [14]

Answer:

1) The partial pressure of SO₂ gas in the larger container = 0.115 atm.

2) The partial pressure of N₂ gas in the larger container = 0.206 atm.

3) The total pressure in the vessel = 0.321 atm.

Explanation:

  • To calculate the partial pressure of each gas, we can use the general law of ideal gas: PV = nRT.

where, P is the partial pressure of the gas in atm,

V is the volume of the vessel in L,

n is the no. of moles of the gas,

R is the general gas constant (R = 0.082 L.atm/mol.K),

T is the temperature of the gas in K.

<u><em>1) What is the partial pressure of SO₂ gas in the larger container?</em></u>

<em>∵ P = nRT/V.</em>

n = mass/molar mass = (3.0 g)/(64.066 g/mol) = 0.047 mol.

R = 0.082 L.atm/mol.K.

T = 26 °C + 273.15 = 299.15 K.

V = 10.0 L. (The volume of the new container)

∴ P = nRT/V = (0.047 mol)(0.082 L.atm/mol.K)(299.15 K)/(10.0 L) = 0.115 atm.

<u><em>2) What is the partial pressure of N₂ gas in the larger container?</em></u>

<em>∵ P = nRT/V.</em>

n = mass/molar mass = (2.35 g)/(28.0 g/mol) = 0.084 mol.

R = 0.082 L.atm/mol.K.

T = 26 °C + 273.15 = 299.15 K.

V = 10.0 L. (The volume of the new container)

∴ P = nRT/V = (0.084 mol)(0.082 L.atm/mol.K)(299.15 K)/(10.0 L) = 0.206 atm.

<u><em>3) What is the total pressure in the vessel?</em></u>

  • According to Dalton's law the total pressure exerted is equal to the sum of the partial pressures of the individual gases.

<em>∵ The total pressure in the vessel = the partial pressure of SO₂ + the partial pressure of N₂.</em>

∴ The total pressure in the vessel = 0.115 + 0.206 = 0.321 atm.

5 0
3 years ago
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