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3 years ago

Which of the following is true of the structures labeled A in the cell membrane?

Physics

2 answers:

matrenka [14]3 years ago

4 0

Answer: a, they are membrane proteins

Explanation:

AysviL [449]3 years ago

4 0

Awnser A is the correct awnser

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As an object falls freely near the surface of the earth, its velocity?

Vsevolod [243]

If it were possible for an object to fall freely near the surface of the Earth,

-- The direction of its velocity would always be "down"; that is, toward the center of the Earth.

-- The size of its velocity would continually increase, at the rate of 9.8 meters per second for every second it falls.

7 0

2 years ago

Use the ratio version of Kepler’s third law and the orbital information of Mars to determine Earth’s distance from the Sun. Mars

zhuklara [117]

Kepler's third law is used to determine the relationship between the orbital period of a planet and the radius of the planet.

The distance of the earth from the sun is $1.50 \times 10^{11}\;\rm m$ .

<h3>What is Kepler's third law?</h3>

Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the radius of their orbits. It means that the period for a planet to orbit the Sun increases rapidly with the radius of its orbit.

$T^2 \propto R^3$

Given that Mars’s orbital period T is 687 days, and Mars’s distance from the Sun R is 2.279 × 10^11 m.

By using Kepler's third law, this can be written as,

$T^2 \propto R^3$

$T^2 = kR^3$

Substituting the values, we get the value of constant k for mars.

$687^2 = k\times (2.279 \times 10^{11})^3$

$k = 3.92 \times 10^{-29}$

The value of constant k is the same for Earth as well, also we know that the orbital period for Earth is 365 days. So the R is calculated as given below.

$365^3 = 3.92\times 10^{-29} R^3$

$R^3 = 3.39 \times 10^{33}$

$R= 1.50 \times 10^{11}\;\rm m$

Hence we can conclude that the distance of the earth from the sun is $1.50 \times 10^{11}\;\rm m$ .

To know more about Kepler's third law, follow the link given below.

brainly.com/question/7783290.

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2 years ago

A thermometer containing 0.10 g of mercury is cooled from 15 degrees celsius to 8.5 degrees celcius. How much energy left the me

loris [4]

To solve this exercise we will use the concept related to heat loss which is mathematically given as

$Q = mC_p \Delta T$

Where,

m = mass

$C_p$ = Specific Heat

$\Delta T =$ Change in temperature

Replacing with our values we have that

$m = 0.1g$

$C_p = 139J/Kg\cdot K \rightarrow$ Specific heat of mercury

$\Delta T = 8.5\°C-15\°C = -6.5\°C \Rightarrow -6.5K$

Replacing

$Q = (0.1*10^3)(138)(-6.5)\\Q = -0.09J$

Therefore the heat lost by mercury is 0.09J

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3 years ago

A symbol on a compass or map that is circular with graded points for the direction is commonly known as a _________. question 13

son4ous [18]

Answer;

-Compass Rose

A symbol on a compass or map that is circular with graded points for the direction is commonly known as a compass rose.

Explanation;

The Earth is a magnet that can interact with other magnets such that, the north end of a compass magnet is drawn to align with the Earth's magnetic field.

A compass rose is a figure on a compass, map, nautical chart, or monument used to display the orientation of the cardinal directions (north, east, south, and west) and their intermediate points. It is a feature on a map that also tells people what direction to go to find certain places on the map

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2 years ago

Read 2 more answers

Compare endoplasmic reticulum to a house cell.

Alenkasestr [34]

The ER mainly folds proteins into sacs and transports proteins through the cell. The ER is a component of both plant and animal cells. The endoplasmic reticulum can be compared to the hallways of a house. Both are networks that allow the materials in the house/cell to be moved around.

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2 years ago