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WARRIOR [948]
2 years ago
8

10a. The y-intercept of the estimated line of best fit is at (0,b). Enter the approximate value of b. Round your estimate to the

nearest whole number.
10b. Enter the approximate slope of the estimated line of best fit in the second box.
Mathematics
1 answer:
vredina [299]2 years ago
4 0

Answer:

The answer is below

Step-by-step explanation:

The equation of a straight line is given as:

y = mx + b; where m is the slope of the line and b is the y intercept (that is value of y at x = 0).

a) From the graph, we can see that the straight line touches the y axis at $100 in which the temperature is 0 degrees. Therefore the y intercept is:

(0, 100)

b) The slope of the line can be gotten by taking two points that the line passes through. Using the points (0, 100) and (12, 500):

slope(m)=\frac{y_2-y_1}{x_2-x_1} =\frac{500-100}{12-0} =33.3

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Answer:

Step-by-step explanation:

3.5y - 12 = 1.5y - 3

2y -12 = -3

2y = 9

y = 4.5

the answer is a. one solution

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3 years ago
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F divides HJ in the ratio 3:1. If H = (-11,7) and J = (5,3), what are the<br> coordinates of F?
Hatshy [7]

Answer:

The coordinates of HF are (1, 4)

Step-by-step explanation:

The parameters of the line are;

The coordinate of the end points are H = (-11, 7), and J = (5, 3)

The ratio by which the point F divides the line = 3:1

The segments in the line are HF, and FJ

Therefore;

The fraction of the length of HJ that is represented by HF = 3/(3 + 1) × HJ = 3/4 × HJ

HF = 3/4 × HJ

Which gives the coordinates of the point F as follows;

Coordinate of F = (-11 +(5 - (-11))×3/4, 7 + (3 - 7)×3/4) =  (1, 4)

The coordinates of F are (1, 4)

We check the length of HF, from the equation for the length to of a line to get;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

l_{HF} = \sqrt{\left (4-7  \right )^{2}+\left (1-(-11)  \right )^{2}} = \sqrt{\left (-3  \right )^{2}+\left (12  \right )^{2}} = 3\cdot \sqrt{17}

Similarly, we check the length of HJ, to get;

l_{HF} = \sqrt{\left (3-7  \right )^{2}+\left (5-(-11)  \right )^{2}} = \sqrt{\left (-4  \right )^{2}+\left (16  \right )^{2}} = 4\cdot \sqrt{17}

The length of HF = 3·√(17)

The length of HJ = 4·√(17)

Therefore, from HF = 3/4× HJ, we have;

HF = 3/4 × 4·√(17) = 3·√(17)

Therefore, the coordinates of HF are (1, 4)

7 0
3 years ago
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