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a_sh-v [17]
2 years ago
15

if graphed in the coordinate plane, would the line y=5x-2 pass through the point (4, 15)? Explain how you arrived at your answer

.
Mathematics
1 answer:
brilliants [131]2 years ago
7 0

Answer:

No

Step-by-step explanation:

If the line did pass through that point, then plugging in the point to the equation would be true. But when you plug in 4 for x, the y would be 18, not 15.

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Verify the identity
Thepotemich [5.8K]

<u>Given</u>:

Given that we need to prove the identity \sin x+\sin x \tan ^{2} x=\tan x \sec x

<u>Proof</u>:

Step 1: Factor out the common term sin x, we get;

\sin x\left(1+\tan ^{2} x\right)=tan \ x \ sec \ x

Step 2: Using the identity 1+tan^2 x=sec^2x

\sin x \sec ^{2} x=tan \ x \ sec \ x

Step 3: Reciprocating sec x, we get;

\sin x \cdot \frac{1}{\cos ^{2} x}=tan \ x \ sec \ x

Step 4: Splitting the denominator, we have;

\frac{\sin x}{\cos x} \cdot \frac{1}{\cos x}=tan \ x \ sec \ x

Simplifying, we get;

\tan x \sec x=\tan x \sec x

Thus, the identity is proved.

5 0
3 years ago
What are two other ways to name RS
kotykmax [81]
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5 0
3 years ago
The volume of the triangular prism is 12.5 m³. The length is 2.5 m and the base is 2 m. What is the width?
Fantom [35]

Answer:

  (4)  5 m

Step-by-step explanation:

You want the length of side x of a right triangular prism with base edge lengths of 2.5 m and 2 m, and a volume of 12.5 m³.

<h3>Volume</h3>

The volume of the prism is given by the formula ...

  V = Bh

where B is the area of the base:

  B = 1/2bh . . . . where b and h are the leg dimensions of the right triangle

Using these formulas together, we have ...

  V = 1/2(2.5 m)(2 m)x

  12.5 m³ = 2.5x m²

Dividing by 2.5 m², we find x to be ...

  (12.5 m³)/(2.5 m²) = x = 5 m

The dimension labeled x has length 5 meters.

6 0
11 months ago
2x + 3y = 5x - y complete the missing value in the solution to the equation
Leto [7]

Answer:

The missing value is(0,0)

Step-by-step explanation:

The complete question is:

2x+3y=5x-y

Complete the missing value in the solution to the equation.

( ,0)

<u>Solution:</u>

We have given:

2x + 3y = 5x - y

Combine the like terms:

2x-5x= -y-3y

-3x = -4y

Both negative signs will be cancelled out by each other.

So we have,

3x = 4y

We have given y = 0

Then

3x = 4*0

3x= 0

Divide both sides by 3

3x/3 = 0/3

x = 0

y=0

Therefore missing value is(0,0)

4 0
3 years ago
Read 2 more answers
Find the quotient of these Complex Numbers. <br><br><br> (5-i) / (3+2i)
JulsSmile [24]

Let the given complex number

z = x + ix = \dfrac{5-i}{3+2i}

We have to find the standard form of complex number.

Solution:

∴ x + iy = \dfrac{5-i}{3+2i}

Rationalising numerator part of complex number, we get

x + iy = \dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}

⇒ x + iy = \dfrac{(5-i)(3-2i)}{3^2-(2i)^2}

Using the algebraic identity:

(a + b)(a - b) = a^{2} - b^{2}

⇒ x + iy = \dfrac{15-10i-3i+2i^2}{9-4i^2}

⇒ x + iy = \dfrac{15-13i+2(-1)}{9-4(-1)} [ ∵ i^{2} =-1]

⇒ x + iy = \dfrac{15-2-13i}{9+4}

⇒ x + iy = \dfrac{13-13i}{13}

⇒ x + iy = \dfrac{13(1-i)}{13}

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0
3 years ago
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