Find the line that is normal to the parabola at the given point
remember that normal means perpendicular
perpendicular lines have slopes that multiply to -1
we can use point slope form to write the equation of the line since we are given the point (1,0)
we just need the slope
take derivitive
y'=1-2x
at x=1
y'=1-2(1)
y'=1-2
y'=-1
the slope is -1
the perpendicular of that slope is what number we can multiply to get -1
-1 times what=-1?
what=1
duh
so
point (1,0) and slope 1
y-0=1(x-1)
y=x-1 is da equation
solve for where y=x-1 and y=x-x² intersect
set equatl to each other since equal y
x-1=x-x²
x²-1=0
factor difference of 2 perfect squares
(x-1)(x+1)=0
set to zero
x-1=0
x=1
we got this point already
x+1=0
x=-1
sub back
y=-1-(-1)²
y=-1-(1)
y=-1-1
y=-2
it intersects at (-1,-2)
Answer:
a = 14
Step-by-step explanation:
Given
9 + a = 23 ( subtract 9 from both sides )
a = 14
Let the number of miles be x.
Then, x miles cost 0.6x.
The initial fixed fee is $5, and the toll is $5.
cost = initial fixed fee + cost per mile + toll
46 = 5 + 0.6x + 5
0.6x + 10 = 46
0.6x = 36
x = 36/0.6
x = 60
You can travel 60 miles.
Pls. see attachment.
The perimeter of the triangle is 146.
Add the 75 and 79 which gives u 154
then subtract it by 180 and should give you 26 as your final answer
