The red colour is the limiting reactant.
Red-blue colour ball and two white balls attached together are reactants.
Red-blue colour ball and two white and one red colour ball attached to each other are products.
<h3>What is a limiting reagent?</h3>
The reactant that is entirely used up in a reaction is called a limiting reagent.
A reactant is a substance that is present at the start of a chemical reaction. The substance(s) to the right of the arrow are called products.
A product is a substance that is present at the end of a chemical reaction.
Hence,
The red colour is the limiting reactant.
Red-blue colour ball and two white balls attached together are reactants.
Red-blue colour ball and two white and one red colour ball attached to each other are products.
Learn more about limiting reagents here:
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Answer:
moles SO42- = 0.0500 L x 0.20 M=0.010
moles Ba2+ = 0.0500 L x 0.10 M = 0.0050
Ba2+ + SO42- = BaSO4 (s)
moles SO42- in excess = 0.010 - 0.0050=0.0050
total volume = 100 mL = 0.100 L
[SO42-]= 0.0050/0.100= 0.050 M
[Na2SO4] = 2 /2 = 1 M
moles Na2SO4 = 2 M x 0.500 L = 0.500
mass Na2SO4 = 0.500 x 142 g/mol=71.0 g
moles MgBr2 = 46 /184 =0.25
moles Br- = 0.25 x 2 = 0.50
[Br-]= 0.50 / 0.50 L = 1 M
Answer: Aristotle
Explanation:Aristotle (c. 384 B.C. to 322 B.C.) was an Ancient Greek philosopher and scientist who is still considered one of the greatest thinkers in politics, psychology and ethics. When Aristotle turned 17, he enrolled in Plato's Academy.
<h3>Answer:</h3>
0.0011 mol
<h3>Solution:</h3>
Data Given:
Mass of Mn = 62.0 mg = 0.062 g
Atomic Mass of Mn = 54.94 g.mol⁻¹
Calculate Moles of Mn as,
Moles = Mass ÷ M.Mass
Putting values,
Moles = 0.062 g ÷ 54.94 g.mol⁻¹
Moles = 0.0011 mol
Chromatography is the separation of a mixture by passing it in solution or suspension or as a vapor through a medium in which the components move at different rates.
