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Lerok [7]
3 years ago
8

3- Write the chemical formula of Alanine and find to which food category it belongs.

Chemistry
1 answer:
lutik1710 [3]3 years ago
3 0

Answer:

C3H7NO2

Explanation:

The chemical formula of Alanine is C3H7NO2 and it belongs to almost all food category because it is present in one food of each food category such as dairy products, meat, nuts, soy, and whole grains etc. Alanine is a nonessential amino acid means that it does not directly obtained from the diet but it can be produced by the body using raw materials present in the food.

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A sample of nitrogen gas, (N2), occupies 45.0 mL at 27.00∘C and 80.0 kPa. What will be the pressure if the gas is cooled to −73.
maxonik [38]

Answer:

The new pressure is 53.3 kPa

Explanation:

This problem can be solved by this law. when the volume remains constant, pressure changes directly proportional as the Aboslute T° is modified.

T° increase → Pressure increase

T° decrease → Pressure decrease

In this case, temperature was really decreased. So the pressure must be lower.

P₁ / T₁ = P₂ / T₂

80 kPa / 300K =  P₂/200K

(80 kPa / 300K) . 200 K = P₂ →  53.3 kPa

6 0
3 years ago
1 point
levacccp [35]

Answer:

A pure substance has a definite chemical composition

4 0
3 years ago
Convert 3828 ml to L
crimeas [40]

Answer:

divide the volume value by 1000

So 3828/1000=3.828

3 0
3 years ago
2
konstantin123 [22]

Explanation:

Regulate body temperature in the extremes of space. maybe

8 0
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Read 2 more answers
A sample of pure lithium chloride contains 16% lithium by mass. What is the % lithium by mass in a sample of pure lithium carbon
Anna35 [415]

Answer:

Percentage lithium by mass in Lithium carbonate sample = 19.0%

Explanation:

Atomic mass of lithium = 7.0 g; atomic mass of Chlorine = 35.5 g; atomic mass of carbon = 12.0 g; atomic mass of oxygen = 16.0 g

Molar mass of lithium chloride, LiCl = 7 + 35.5 = 42.5 g

Percentage by mass of lithium in LiCl = (7/42.5) * 100% = 16.4 % aproximately 16%

Molar mass of lithium carbonate, Li₂CO₃ = 7 * 2 + 12 + 16 * 3 =74.0 g

Percentage by mass of lithium in Li₂CO₃ = (14/74) * 100% = 18.9 % approximately 19%

Mass of Lithium carbonate sample = 2 * 42.5 = 85.0 g

mass of lithium in 85.0 g Li₂CO₃ = 19% * 85.0 g = 16.15 g

Percentage by mass of lithium in 85.0 g Li₂CO₃ = (16.15/85.0) * 100 % = 19.0%

Percentage lithium by mass in Lithium carbonate sample = 19.0%

3 0
3 years ago
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