1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elodia [21]
2 years ago
13

Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 2.55 g

of sodium and 3.93 g of chlorine. Being consistent with the law of constant composition, also called the law of definite proportions or law of definite composition, which set of masses could be the result of the decomposition of the other sample
Chemistry
1 answer:
Charra [1.4K]2 years ago
3 0

Answer:

4.71 g of sodium and 7.25 g of chlorine

Explanation:

<em>Note: The question is incomplete. the complete question is given below:</em>

<em>Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 2.55 g of sodium and 3.93 g of chlorine. Being consistent with the law of constant composition, also called the law of definite proportions or law of definite composition, which set of masses could be the result of the decomposition of the other sample?</em>

<em>4.71 g of sodium and 3.30 g of chlorine</em>

<em>4.71 g of sodium and 7.25 g of chlorine</em>

<em>4.71 g of sodium and 1.31 g of chlorine</em>

<em>4.71 g of sodium and 13.7 g of chlorine</em>

The law of definite proportions states that all pure samples of a particular chemical compound contain the same elements combined in the same proportion by mass.

This means that irrespective of the source of any sample of a pure chemical compound, the constituents elements are always combined in the same mass ratio.

In the first sample, the mass ratio of Sodium to chlorine is given below:

mass of sodium = 2.55 g

mass of chlorine = 3.93 g

mass ratio; sodium to chlorine = 2.55 / 3.93 = 0.65

From the set of masses give above, we can determine the result of the decomposition of the second sample.

4.71 g of sodium and 3.30 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 3.30 = 1.43

4.71 g of sodium and 7.25 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 7.25 = 0.65

4.71 g of sodium and 1.31 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 1.31 = 3.59

4.71 g of sodium and 13.7 g of chlorine

mass ratio; sodium to chlorine = 4.71 / 13.7 = 0.34

From the results above, the correct set of masses for the second sample is 4.71 g of sodium and 7.25 g of chlorine

You might be interested in
S
N76 [4]

Answer:

B

Explanation:

B

4 0
2 years ago
54
skelet666 [1.2K]

Answer:

less than 5 centimeters because it is a nonvascular plant

Explanation:

Mosses are a group of plants under the division Bryophyta. They are said to be the most primitive plant life in existence as they lack true roots, stems and leaves. They also lack vascular system, hence, they are regarded as non-vascular plants. They usually grow in very small sizes (about 0.2 - 10cm).

According to this question, Penny bought a club moss plant for her water garden and needs to know how tall the plant will grow so she know how much space it will need. Since it is a miss plant that lacks vascular tissues i.e. nonvascular, it will likely grow less than 5 centimeters in height.

7 0
2 years ago
The following charges on individual oil droplets were obtained during an experiment similar to Millikan's. Determine a charge fo
RSB [31]

Answer:

- 1.602 x 10⁻¹⁹coulombs

Explanation:

Charge on individual oil droplet would be multiple of charge on one electron . So we will find out the minimum common factor of given individual charges that is the LCM of all the charges given.

LCM of given charges like 3.204 , 4.806 ,8.01 and 14.42 . We have neglected the power of ten( 10⁻¹⁹)  because it is  already a common factor to all.

The LCM  is 1.602 . So charge on electron is 1.602 x 10⁻¹⁹.

4 0
3 years ago
If a molecule has an empirical formula of C2H2O and a molecular mass of 84.0 g/mol, what is the molecular formula?
lord [1]

Answer:

=C₄H₄O₂

Explanation:

Given the empirical formula of a molecule, the he the quotient of the molecular mas and and the empirical mass=constant.

84.0 g/mol/mass of(C₂H₂O)=constant

=84/(12×2+1×2×16)

=84/42

=2

Therefore, the molecular formula is (C₂H₂O)₂=C₄H₄O₂

6 0
3 years ago
Read 2 more answers
Warm air _____.
svp [43]

Answer:

cools as it rises, then sinks back down

Explanation:

The movement of air is a convection current. Convection currents occur when warm air rises, cools down, and sinks due to gained density, replacing the warm air closer to the ground, creating a cycle.

5 0
3 years ago
Other questions:
  • In this Punnett square, what is the probability of the offspring being a heterozygous purple flower
    9·1 answer
  • A solution is prepared by dissolving 15.0 g of NH3 in 250 g of water. The density of the resulting solution is 0.974 g/mL. The m
    9·1 answer
  • Which of the following compounds is not ionic?
    9·1 answer
  • HELP QUICK!
    5·2 answers
  • What is a particulate?
    13·2 answers
  • What is the main idea and Detail/Evidence of Light microscopes​
    13·2 answers
  • A fire is an example of an exothermic reaction. Which of the following best
    9·1 answer
  • Help me with these two please​
    9·2 answers
  • The galaxies pictured above would best be classified as
    10·1 answer
  • HI(aq)+NaOH(aq)→ <br> what the final balanced chemical equation with the phases included
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!