Answer:
1:8
Step-by-step explanation:
Given that in square ABCD, point M is the midpoint of side AB and point N is the midpoint of side BC.
Let the side of the square be a.
Area of square ABCD = 
The triangle AMN is having two legs of a right triangle as half of side of the square
i.e. Triangle AMN has base = height = a/2
So area of triangle AMN = 
Ratio of the area of triangle AMN to area of square ABCD
= 1:8
I think it would be 2x2uehhehehehegdgwgegege
Complete question :
Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?
Answer:
61
Step-by-step explanation:
Given the following :
Total number of students = 4 + 1 missing = 5
Score on the four avaliable papers = 60, 62, 56, 57
Average score of the 5 papers = 59.2
Score on missing paper :
Sum of each score / number of papers
Sum of each score = sum of available scores + missing score
Let missing score = m
(60 + 62 + 56 + 57 + m) = 235 + m
Recall:
Average = total sum / number of observations
Hence,
59.2 = (235 + m) / 5
59.2 × 5 = 235 + m
296 = 235 + m
m = 296 - 235
m = 61
Missing score = 61
X = -6 + y...so we sub in -6 + y for x in the other equation
x - 3y = 28
-6 + y - 3y = 28
-2y - 6 = 28
-2y = 28 + 6
-2y = 34
y = -34/2
y = - 17
x = -6 + y
x = -6 - 17
x = - 23
solution is (-23,-17)
