Using your knowledge of colligative properties explain whether sodium chloride or calcium chloride would be a more effective sub
1 answer:
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Answer:
Use a ratio of 0.44 mol lactate to 1 mol of lactic acid
Explanation:
John could prepare a lactate buffer.
He can use the Henderson-Hasselbalch equation to find the acid/base ratio for the buffer.
He should use a ratio of 0.44 mol lactate to 1 mol of lactic acid.
For example, he could mix equal volumes of 0.044 mol·L⁻¹ lactate and 0.1 mol·L⁻¹ lactic acid.
Answer: 11.0 g of calcium will react with 10.0 grams of water.
Explanation:
To calculate the moles, we use the equation:
moles of
The balanced chemical equation is:
According to stoichiometry :
2 moles of require = 1 mole of
Thus 0.55 moles of require=
of
Mass of
Thus 11.0 g of calcium will react with 10.0 grams of water.