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Ivanshal [37]
2 years ago
7

Resuelve las siguientes situaciones problémicas utilizando el método gráfico 4. Dos números son tales que el doble del primero m

enos el segundo es 8 y la suma de los números es uno. ¿Cuáles son los números?
Mathematics
1 answer:
Alex Ar [27]2 years ago
4 0

Answer:

Ja niewiem pseprasam baardzo bardzo bardzo bardzo bardzo bardzo bardzo bardzo bardzo bardzo bardzo bardzo bardzo bardzo bardzo bardzo bardzo bardzo bardzo

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Expand and combine like terms.<br> (3c^4-5c^6)^2
lora16 [44]

Answer:

9c^{8} -30c^{10} + 25c^{12}

Step-by-step explanation:

We can use formula (a-b)² = a² -2ab + b².

In our example a = 3c^4 and b = 5c^6

(3c^{4} - 5c^{6})^{2} = [3c^{4} ]^{2} - 2*3c^{4} *5c^{6} + [5c^{6}]^{2}=\\=9c^{8} -30c^{10} + 25c^{12}

4 0
3 years ago
You roll a six-sided number cube. Which events are mutually exclusive?
maksim [4K]
Events are mutually exclusive only if they cannot both be true.
Only C is alright.

4 is a multiple of two so it can't be right.
Same logic works for B.

And then 2 is prime so then D is out too.
7 0
3 years ago
Read 2 more answers
Solve the given inequality and graph the solution on a number line.
raketka [301]

Answer:

sorry agnor me

Step-by-step explanation:

plz egnore my ideodik nis

4 0
3 years ago
Read 2 more answers
| x - 1 | = 5x + 10<br> Check for extraneous solutions.
Ronch [10]
[x-1]=5x+10

We have two equations:
1) x-1=5x+10

x-1=5x+10
x-5x=10+1
-4x=11
x=-11/4

2) x-1=-(5x+10)

x-1=-(5x+10)
x-1=-5x-10
x+5x=-10+1
6x=-9
x=-9/6=-3/2

we have two  possible solutions:
solution₁;       x=-11/4
solution₂:       x=-3/2

we check it out:
1) x=-11/4
[x-1]=5x+10
[-11/4  - 1]=5(-11/4)+10
[(-11-4)/4]=-55/4  + 10
[-15/4]=(-55+40) /4
15/4≠-15/4   This solution don´t work.

2) x=-3/2
[x-1]=5x+10
[-3/2  - 1]=5(-3/2)+10
[(-3-2)/2]=-15/2  + 10
[-5/2]=(-15+20)/2
5/2=5/2; this solution works.

Therefore:

Answer: x=-3/2.
8 0
3 years ago
Read 2 more answers
Find the distance between each pair of points. Round your answer to the nearest tenth, if necessary. Hint: Use the Pythagorean T
Paul [167]

The distance between two points on the plane is given by the formula below

\begin{gathered} A=(x_1,y_1),B=(x_2,y_2) \\ \Rightarrow d(A,B)=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2} \end{gathered}

Therefore, in our case,

A=(-1,-3),B=(5,2)

Thus,

\begin{gathered} \Rightarrow d(A,B)=\sqrt[]{(-1-5)^2+(-3-2)^2}=\sqrt[]{6^2+5^2}=\sqrt[]{36+25}=\sqrt[]{61} \\ \Rightarrow d(A,B)=\sqrt[]{61} \end{gathered}

Therefore, the answer is sqrt(61)

In general,

-(-n)=n

Remember that

-n=(-1)\cdot n

Therefore,

\begin{gathered} a-(-n)=a+(-1)(-n)=a+(-1)(-1\cdot n)=a+(-1)^2\cdot n=a+1\cdot n=a+n \\ \Rightarrow a-(-n)=a+n \end{gathered}

6 0
1 year ago
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