If we connect Gabe's current position to the top of the building, to the bottom of the building and back to Gabe, we form a right triangle with the height of 250 m and the angle opposite to the height being equal to 19°. If we let x be his distance from the building, we use the trigonometric formula,
tan 19° = x/250 m
The value of x from the equation is 86.08 m. Thus, the answer is 86.08 m.
Answer:
3,500,000 J
Explanation:
WORK = POWER * TIME
WORK= 5400 * 640
=6456000 J = 3,500,000 J
Answer:
s = 90 m
a = 56 m/s²
Explanation:
I will ASSUME that your equation is silly as it reduces to V = 11t which is constant, and that you mean V = 9t² + 2t
Position is the integral of differential velocities
s =
s = 3t³ + t² | from 0 to 3
s = 3(3)³ + 3² - (0) = 90 m
acceleration is the derivative of velocity
a = v' = 18t + 2
a(3) = 18(3) + 2 = 56 m/s²
Question: Initially, the car travels along a straight road with a speed of 35 m/s. If the brakes are applied and the speed of the car is reduced to 13 m/s in 17 s, determine the constant deceleration of the car.
Answer:
1.29 m/s²
Explanation:
From the question,
a = (v-u)/t............................ Equation 1
Where a = deceleration of the car, v = final velocity of the car, u = initial velocity of the car, t = time.
Given: v = 13 m/s, u = 35 m/s, t = 17 s.
a = (13-35)/17
a = -22/17
a = -1.29 m/s²
Hence the deceleration of the car is 1.29 m/s²