Answer:
On Earth all bodies have a weight, or downward force of gravity, proportional to their mass, which Earth's mass exerts on them. Gravity is measured by the acceleration that it gives to freely falling objects. At Earth's surface the acceleration of gravity is about 9.8 metres (32 feet) per second per second.
Answer:
The magnitude of the electrostatic force is 120.85 N
Explanation:
We can use Coulomb's law to find the electrostatic force between the down quarks.
In scalar form, Coulomb's law states that for charges 
and 
separated by a distance d, the magnitude of the electrostatic force F between them is:
where 
is Coulomb's constant.
Taking the values:
and knowing the value of the Coulomb's constant:
Taking all this in consideration:
Answer:
Transition metal.
Explanation:
Reason;in periodic table gold is third element in eleventh column. So its classified as TRANSITION METAL. Gold contain 79 protons, 79 electrons and 118 neutrons and gold is the most abundant isotope.
Hope i helped you..
When something moves on a round track, the guidance of the something's velocity must continually switch. A switching velocity means that there must be an acceleration. This acceleration is horizontal to the guidance of the velocity. This is said as “the radial acceleration”, or “centripetal acceleration” ("centripetal" means "center searching"). The “radial acceleration” is equal to “the square of the velocity”, divided by “the radius of the circular path of the object”. The unit of the “centripetal acceleration” is m/s².
where,
"v" = "velocity" (m/s) and "r" = "radius of motion of the object" (m)
Over the first 30.0 s, the undergoes a displacement of
(12 m/s) * (30.0 s) = 360 m
Over the next 8.00 s, the car accelerates from 12 m/s to a top speed of
12 m/s + (1.5 m/s²) * (8.00 s) = 24 m/s
and over this time interval, it is displaced an additional
(12 m/s) * (8.00 s) + 1/2 (1.5 m/s²) * (8.00 s)² = 144 m
For the last 12.0 s, the car moves at a constant speed of 24 m/s to cover a distance of
(24 m/s) * (12.0 s) = 288 m
So the car's net displacement is 360 m + 144 m + 288 m = 792 m. (The net displacement is the same as distance in this case because the car moves in only one direction.)
