Hello!
A stretched spring has 5184 J of elastic potential energy and a spring constant of 16,200 N/m. What is the displacement of the spring ?
Data:
For a spring (or an elastic), the elastic potential energy is calculated by the following expression:
Where k represents the elastic constant of the spring (or elastic) and x the deformation or displacement suffered by the spring.
Solving:
Answer:
The displacement of the spring = 0.8 m
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Answer:
yes
Explanation:
using law of HC(heat capacity), which is
- heat loss=heat gain
- energy H=MCQ
Where M is mass of substance,C is specific heat capacity, and Q is temperature change
In case of two substance
- the H = Mc*Cc*Q+Mw*Cw*Q(provided the initial and final temperature are given)
The answer is 4.0 kg since the flywheel comes to rest the
kinetic energy of the wheel in motion is spent doing the work. Using the
formula KE = (1/2) I w².
Given the following:
I = the moment of inertia about the
axis passing through the center of the wheel; w = angular velocity ; for the
solid disk as I = mr² / 2 so KE = (1/4) mr²w². Now initially, the wheel is spinning
at 500 rpm so w = 500 * (2*pi / 60) rad / sec = 52.36 rad / sec.
The radius = 1.2 m and KE = 3900 J
3900 J = (1/4) m (1.2)² (52.36)²
m = 3900 J / (0.25) (1.2)² (52.36)²
m = 3.95151 ≈ 4.00 kg
B boiling point because you used heat and it turned to vapor so it was boiled
Answer:
a) B=0.008 T
b) +z direction
Explanation:
<u>solution:</u>
a) The magnetic force:
F=i*l*B
Solve for B:
B=0.008 T
b) According to the left hand rule, the magnetic field is in the +z direction
